A. What is the distance from point O to the pendulum's mass center, G? (include units with answer)B. What is the pendulum's moment of inertia about an axis perpendicular to the screen and passing through point G? (include units with answer)C. What is the pendulum's moment of inertia about an axis perpendicular to the screen and passing through point O? (include units with answer) **Diagram Description:**The diagram illustrates a pendulum consisting of a slender rod and a thin plate. Key elements of the diagram include:- **Rod**: Extends vertically from point O at the top to point A at the bottom, with length denoted as \( L \).- **Length \( L \)**: Given as \( 1.7 \, \text{m} \).- **Mass per Unit Length**: Rod has a mass per unit length of \( 2.8 \, \text{kg/m} \).- **Plate**: A thin plate attached at point A, shown as a circular disk.- **Mass per Unit Area**: Plate has a mass per unit area of \( 10.0 \, \text{kg/m}^2 \).- **Plate Dimensions**: - Inner radius is shown as \( 0.1 \, \text{m} \). - Outer radius is \( 0.3 \, \text{m} \).**Associated Labels:**- \( O \): Top pivot point of the pendulum.- \( A \): Base connection point of the rod and plate.- \( G \): Center of mass of the plate.- \( y \): Vertical axis marked along the length of the rod.**Image Caption:** The pendulum shown consists of a slender rod with mass per unit length of \( 2.8 \, \text{kg/m} \), and a thin plate with mass per unit area of \( 10.0 \, \text{kg/m}^2 \). In the figure, \( L = 1.7 \, \text{m} \).

Name: A. What is the distance from point O to the pendulum's mass center, G
Uploaded: 2024-03-20T06:56:55.000Z
Channel: Bartleby
Description: A. What is the distance from point O to the pendulum's mass center, G? (include units with answer)B. What is the pendulum's moment of inertia about an axis perpendicular to the screen and passing through point G? (include units with answer)C. What i

Answered: Image /qna-images/answer/da6a9eb5-e2b9-4c18-9695-65922b9c102b.jpg

Answered: G 0.1 m 0.3 m The pendulum shown…

Engineering

Mechanical Engineering

G 0.1 m 0.3 m The pendulum shown consists of a slender rod with mass per unit length of 2.8 kg/m, and a thin plate with mass per unit area of 10.0 kg/m². In the figure, L = 1.7 m.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

It is common to hang objects on doorknobs and over-the-door hooks. There is a limit to the amount of weight that a door can hold because of the forces exerted on the hinges. A door of height h = 2.5 m and width h/2 has a mass of M = 36 kg. The mass is distributed uniformly, so the center of mass is located at the geometric center of the door. One hinge is located a distance h/4 from the top of the door. The second hinge is a distance h/4 from the bottom of the door. Refer to (a) in the figure. The door’s weight is supported entirely by the two hinges and each hinge supports half of the weight. In other words, the vertical force exerted by each hinge is exactly one half of the total weight, including any additional load. For this problem, take the positive y-direction to be directly upward and the positive x-direction pointing from the hinge side of the door to the knob side. 1.) calculate the force, with its sign in Newtons that the upper hinge exerts on the door in the x axis.…
The shaft in the figure, carrying three unbalanced masses, is rotating at a constant speed hızla = 10 r / s. Find the balancing values (kg.mm) and their positions in case of balancing in DI and DII planes.
John is pushing his daughter Rachel in a wheelbarrow when it is stopped by a brick 8.00 cm high (see the figure below). The handles make an angle of 0 = 16.0° with the ground. Due to the weight of Rachel and the wheelbarrow, a downward force of 411 N is exerted at the center of the wheel, which has a radius of 18.5 cm. Assume the brick remains fixed and does not slide along the ground. Also assume the force applied by John is directed exactly toward the center of the wheel. (Choose the positive x-axis to be pointing to the right.) ..(a.).What force.(in N) must John apply along the handles to just start the wheel over the brick? Enter a number. differs from the correct answer by more than 10%. Double check your calculations. N (b) What is the force (magnitude in kN and direction in degrees clockwise from the −x-axis) that the brick exerts on the wheel just as the wheel begins to lift over the brick? magnitude KN direction o clockwise from the -x-axis
A 50 kg drum is suspended by a rope below a ring A, as shown below. The ring is supported by another rope (AB) and by a spring (AC). AC has a spring constant of k = 200 N/m. What is the unstretched length of spring AC? spfing 2.5 m B 3 1 1.5 m 50 kg drum
A uniform rod (mass = 1.8 kg) is 1.5 m long. The rod is pivoted about a horizontal, frictionless pin through one end. The rod is released from rest in a horizontal position. What is the angular speed of the rod (in rad/s) when the rod makes an angle of 23° with the horizontal?. The moment of inertia of the rod about this axis is given by (1/3)ML2.
Q3. As shown on the right in image below, the force Facting on the box varies with displacement s, and the coefficient in the image, C = 14. Determine the work done by force Fto the box when the box has displaced s = 1.9 m. Please pay attention: the numbers may change since they are randomized. Negative sign must be included if the work done is negative. Your answer must include 2 places after the decimal point, and proper SI unit. F (N) F 5 3 S 4 C s (m) 1 2
7. The arrangement in the drawing shows a block (mass = 14.0 kg) that is held in position on a frictionless incline by a cord (length = 0.582 m). The mass per unit length of the cord is 1.30 x 10-2 kg/m, so the mass of the cord is negligible compared to the mass of the block. The cord is being vibrated at a frequency of 166 Hz (vibration source not shown in the drawing). What is the smallest angle 0 between 15.0° and 90.0° at which a standing wave exists on the cord?
Consider why a wheelbarrow is helpful to move heavy stuff. Below is an example wheelbarrow loaded with 15 kg of stuff. 9. 1.25 m Center of mass € 0.45 m of body and handle Fx Fy 1.20 m 0.55 m 0.30 m The wheelbarrow has a single wheel of mass 2.5 kg, radius of 0.30 m. The body of the wheelbarrow and the stuff has a combine mass of 17.5 kg acting at the center of mass shown. The horizontal and vertical components of the force that we push with is named F and Fy, respectively. a. Draw separate free body diagrams for the wheel and for the wheelbarrow body. b. What force F and F, do you have to apply to the wheelbarrow to accelerate the wheelbarrow at 1.0 m/s2 to the right? (Hint: The body of the wheelbarrow does not rotate.)
A board sits in equilibrium. On the left end, there is a wire that supports the board from the ceiling, and to the right, there is a sawhorse that supports the board from the ground. The sawhorse is a distance d= 1/5l from the right edge of the board. There is a block with mass ms= 4.5kg that is a distance 3/4l from the right edge of the board. Finally the board has a mass mb= 11kg. c) Write down Newton's 2nd law. Put the equation in terms of mb, ms, g, T, and Fn. Where T is the tension in the wire, and Fn is the normal force of the sawhorse on the board. d) Write down Newton's 2nd Law for rotations. Put the equation in terms of l, mb, ms, g, T, and Fn.
A uniform board has a length L = 4.0 m and rests horizontally and somewhat above the ground on two cylinders of wood, each supporting the board at a distance of D= 0.75 m from the corresponding end of the board. (The axis of each cylinder is perpendicular to the length of the board.) The board has a mass of ma = 40 kg. A person with a mass of me = 50 kg is about to step on one end of the board. Our goal is to identify if it is safe for the person to step on the board. A. On the diagram below, draw all the forces acting on the board. Assume the person has just stepped on the left end. B. Each of the two wodden cylinders exerts an upward force on the board. Which one of those two forces is larger? If this detail is not evident from your force diagram, redraw it. C. If the board does end up starting to tilt after the person steps on it, what does that imply about the normal force that the right support exerts? D. Is it safe for the person to step on the board? Hint: Around which point…
Three identical 8.60-kg masses are hung by three identical springs, as shown in the figure. (Figure 1) Each spring has a force constant of 5.90 kN/m and was 11.0 cm long before any masses were attached to it. Make a free-body diagram for the top mass. Draw the vectors starting at the black dot at the center of the top mass.
Determine the magnitude and direction of the angle theta of the force FAB that must be exerted on bar AB to maintain equilibrium of the system. The suspended mass is 110 kg. Neglect the size of the pulley at A and treat all pulleys as smooth. What should happen to maintain the equilibrium of the system if FAB acts with an angle theta= 0°?Consider g = 9.81 m/s2.