f(x) = (-3x³ + 4) 7, which of the following is f'(x)? f' (x) = 63x² (-3x° + 4)-8 - f' (x) = 63x(-3x + 4)-8 O f (x) = 63x²(-3x³ + 4)-7 O f'(x) = -63x²(-3x³ + 4)-8

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A:

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A:

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A: Solution of first derivative

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A:

Q: f"(x) = 4x – 2 and f'(-3) = -3 and f(-3) = –6. Find f' (x) = %3D and find f(4) :

A: f''(x)=4x-2 f'(-3)=-3 , f(-3)=-6

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A: F

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A:

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A:

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A:

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A:

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A:

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A:

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A:

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Q: given that the derivative of f(x)=10 5√x^3−√x^7+6 3√x^8−3 is 6x−2/5−7/2x^5/2+16x^5/3, what does 2+2…

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A: