f(x) = 0.5x-6x +21 %3D = 0.5(x²-12x+42) = 0.5(x²-12x+ 0.5((x-6)²+6) 0.5(x-6)2 + 3 %3D 36-36 +42) %3D = D. %3D

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.2: Exponents And Radicals
Problem 12E
Question

Quadratic function into vertex form

image is from the teaching video, I do not understand how he gets =36 -36 in the third line

(A) f(x) =
0.5x-6x+21
经)
-12
3D36
0.5(x²-12x +42)
0.5(x-12x+36-36+42.)
= 0.5((x-c)²+ 6)
0.5((x-6)²+6)
0.5(x-6)
3.
%3D
%3D
%3D
%3D
Transcribed Image Text:(A) f(x) = 0.5x-6x+21 经) -12 3D36 0.5(x²-12x +42) 0.5(x-12x+36-36+42.) = 0.5((x-c)²+ 6) 0.5((x-6)²+6) 0.5(x-6) 3. %3D %3D %3D %3D
Expert Solution
Step 1

f(x)=0.5x2-6x+21       =0.5x2-12x+42

Now to do a complete square we need to add and subtract some constant and that constant is given by:

(1) the coefficient of x is -12,

(2) divide the coefficient by 2 -122=-6 ,

(3) now take a square of that number (-6)2=36

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