Furnco manufactures desks and chairs. Each desk uses 4 units of wood, and each chair uses 3. A chair contributes $25 to pront, and a desk contributes $40. Marketing restrictions require that the number of chairs produced be at least twice the number of desks produced. If 20 units of wood are available, formulate an LP to maximize Furnco's profit. Let a be the number of desks produced, and y be the number of chairs produced. Then, the formulation of the problem is maximize z = 40x + 25y Subject to: 3x + 4y0 < 20 y > 2x x >0 y > 0 maximize z = 40x + 25y %3D Subject to: 4x + 3y0 < 20 Y< 2x x > 0
Furnco manufactures desks and chairs. Each desk uses 4 units of wood, and each chair uses 3. A chair contributes $25 to pront, and a desk contributes $40. Marketing restrictions require that the number of chairs produced be at least twice the number of desks produced. If 20 units of wood are available, formulate an LP to maximize Furnco's profit. Let a be the number of desks produced, and y be the number of chairs produced. Then, the formulation of the problem is maximize z = 40x + 25y Subject to: 3x + 4y0 < 20 y > 2x x >0 y > 0 maximize z = 40x + 25y %3D Subject to: 4x + 3y0 < 20 Y< 2x x > 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:maximize z = 40x + 25y
Subject to:
3x + 4y0 < 20
Y< 2x
x >0
y > 0
maximize z = 40x + 25y
Subject to:
4x + 3yD < 20
y > 2x
x >0
y >0
Transcribed Image Text:Furnco manufactures desks and chairs. Each desk uses 4 units of wood, and each chair uses 3. A chair
contributes $25 to pront, and a desk contributes $40. Marketing restrictions require that the number of chairs
produced be at least twice the number of desks produced. If 20 units of wood are available, formulate an LP to
maximize Furnco's profit.
Let a be the number of desks produced, and y be the number of chairs produced. Then, the formulation of the
problem is
maximize z = 40x + 25y
Subject to:
3x + 4y0 < 20
y > 2x
r >0
y > 0
maximize z = 40x + 25y
%3D
Subject to:
4x + 3y0 < 20
Y< 2x
x >0
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