Answered: function iterFunc(x) { return x^3 + x -…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Concept explainers

Question

function iterFunc(x) {
return x^3 + x - 1
}
oldEst = 0
tol = 0.00005

error = 1
while (error > tol)
newEst = iterFunc(oldEst)
print(newEst)
error = abs(newEst - oldEst)
oldEst = newEst
}

Edit this psuedocode to make it work in python, the output should be 0.6823 as this is a method of root finding!

Expert Solution

Step 1: Providing the algorithm

Define the func(x) function that returns the value of x^3 + x - 1.
Define the func_derivative(x) function that returns the value of 3x^2 + 1.
Set the initial guess for the root to 0.
Set the tolerance for convergence to 0.00005.
Set the maximum number of iterations to 1000.
Initialize the error to a value greater than the tolerance.
Initialize the number of iterations to 0.
Start a while loop that runs as long as the error is greater than the tolerance and the number of iterations is less than the maximum number of iterations.
Calculate the new estimate for the root using the old estimate and the Newton-Raphson formula.
Calculate the error between the new estimate and the old estimate.
Update the old estimate with the new estimate.
Increment the number of iterations.
End the while loop.
Print the estimated root rounded to 4 decimal places.

Step by step

Solved in 4 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions