From the titration of 50.00 mL of FeSO4 0.2500 mol L-1 with a solution of K2Cr2O7 0.1000 mol L-1 under acidic conditions, in which [H+] = 1.00 mol L-1, calculate the Potential (E) of the system for adding the following volumes of K2Cr2O7 solution: i) 5.00 mL ii) volume at the stoichiometric point (PE) iii) 22.00 mL
From the titration of 50.00 mL of FeSO4 0.2500 mol L-1 with a solution of K2Cr2O7 0.1000 mol L-1 under acidic conditions, in which [H+] = 1.00 mol L-1, calculate the Potential (E) of the system for adding the following volumes of K2Cr2O7 solution: i) 5.00 mL ii) volume at the stoichiometric point (PE) iii) 22.00 mL
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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From the titration of 50.00 mL of FeSO4 0.2500 mol L-1 with a solution of K2Cr2O7 0.1000 mol L-1 under acidic conditions, in which [H+] = 1.00 mol L-1, calculate the Potential (E) of the system for adding the following volumes of K2Cr2O7 solution:
i) 5.00 mL
ii) volume at the stoichiometric point (PE)
iii) 22.00 mL
![E° (volts)
REACTION
Au+ + 3e
O, + 4H* + 4e
Pt2+ + 2e
Ag* + e
Fe* + e
O, + 2H;O + 4e
Cu²+ + 2e
2H* + 2e
Pb2+ + 2e
Sn2+ + 2e
Ni* + 2e
Co+ + 2e
Cd²+ + 2e
Fe+ + 2e
Cr* + 3e
Zn+ + 2e
AP* + 3e
Mg* + 2e -
Na* + e - Na
K* + e - K
→ Au
2H;O
Pt
+1.420
+1.229
-+1.2
+0.800
» Ag
- Fe2+
+0.771
4(OH")
Cu
+0.401
+0.340
0.000
Pb
-0.126
-0.136
-0.250
Sn
Ni
Co
-0.277
-0.403
» Cd
→ Fe
-0.440
→ Cr
→ Zn
» Al
→ Mg
-0.744
-0.763
-1.662
-2.363
-2.714
-2.924](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc6fb24e4-9267-4c86-886f-e86e315e2775%2F47a5cfaa-f7b5-436f-b886-5a3ea3f680c7%2Fne71x14_processed.png&w=3840&q=75)
Transcribed Image Text:E° (volts)
REACTION
Au+ + 3e
O, + 4H* + 4e
Pt2+ + 2e
Ag* + e
Fe* + e
O, + 2H;O + 4e
Cu²+ + 2e
2H* + 2e
Pb2+ + 2e
Sn2+ + 2e
Ni* + 2e
Co+ + 2e
Cd²+ + 2e
Fe+ + 2e
Cr* + 3e
Zn+ + 2e
AP* + 3e
Mg* + 2e -
Na* + e - Na
K* + e - K
→ Au
2H;O
Pt
+1.420
+1.229
-+1.2
+0.800
» Ag
- Fe2+
+0.771
4(OH")
Cu
+0.401
+0.340
0.000
Pb
-0.126
-0.136
-0.250
Sn
Ni
Co
-0.277
-0.403
» Cd
→ Fe
-0.440
→ Cr
→ Zn
» Al
→ Mg
-0.744
-0.763
-1.662
-2.363
-2.714
-2.924
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