i need help with the calculations. i am messing up something in the math Orifice MeterFrom the theory, the equation governing the flow rate through a orifice meter is shown as follows:The data obtained for orifice meter from the experiment is summarized as followsΔΡNo.unitsThen,12345Flow rate (gpm)Gallons Per Minute545432Sample CalculationsInner diameter of the tube = 0.590/n = 0.014986mQ₂Orifice Bore = 0.311in = 0.078994m.A₂ =inV₂ =7032MD₂²Q₂ = A₂V₂ CA₂C-Fin200 160150 125 25127 100 27= A₂V₂ = A₂60P1-P223in1092(P₁-P₂)√(¹-())40 1.016 9963.912????2(P₁-P₂)√(1-3))2(P₁-P₂)√(1-3))AP=P1-P2T(0.0078994m)²4=m????(2)-(-AP=P1-P2Pa????????velocity0.078994m0.014986mm/s5.25312??????= 49.00925 x 10-6m²??flow rateQorim³/s0.0002574512(9963.912)kgm/s²1000kg/m³(1-(0.277854)²)????????= 0.277854Actualflow rateGotm³/s0.0003330.00030.000250.0001830.000117= 5.25312m/s(5.25312m (49.00925 x 10-6m²) = 0.000257451m²/sThe flow rate in this case is lower than the actual flow rate. This is due to the loss in the flow rate caused by the turbulence in the orifice.

The inner diameter is The outer diameter is The difference in pressure is

From the theory, the equation governing the flow rate through a orifice meter is shown as follows: 2(P₁-P₂) Q₂-A₂V₂ CA₂ *√(¹-(;;)) The data obtained for orifice meter from the experiment is summarized as follows No. units Then, 1 2 3 4 5 Flow rate (gpm) Gallons Per Minute 5 45 4 3 2 Sample Calculations Inner diameter of the tube =0.590 in = 0.014986m Orifice Bore = 0.311in = 0.078994m. = om in 32 200 160 150 127 70 60 TD₂² C-F P1- P2 in Q₂ = A₂V₂ = A₂ 125 100 AP 2 in 25 27 10 9 P2 2(P₁-P₂) √(¹-(3)) 40 1.016 9963.912 5.25312 2 (P₁-P₂) √(¹-(A)) 1- E T(0.0078994m)² ?? ?? ?? ?? (-) - AP= P1-P2 Pa ?? ?? ?? ?? velocity m/s 0.078994m 0.014986m 5.25312m ?? = 49.00925 x 10-6m² ?? ?? ?? flow rate Qori m³/s 0.000257451 2(9963.912)kgm/s² 1000kg/m³(1-(0.277854)²) 3333 ?? = 0.277854 Actual flow rate Qact m³/s 0.000333 0.0003 0.00025 0.000183 0.000117 = 5.25312m/s (49.00925 x 10-6m²) = 0.000257451m³/s The flow rate in this case is lower than the actual flow rate. This is due to the loss in the flow rate caused by the turbulence in the orifice.

From the theory, the equation governing the flow rate through a orifice meter is shown as follows: 2(P₁-P₂) Q₂-A₂V₂ CA₂ *√(¹-(;;)) The data obtained for orifice meter from the experiment is summarized as follows No. units Then, 1 2 3 4 5 Flow rate (gpm) Gallons Per Minute 5 45 4 3 2 Sample Calculations Inner diameter of the tube =0.590 in = 0.014986m Orifice Bore = 0.311in = 0.078994m. = om in 32 200 160 150 127 70 60 TD₂² C-F P1- P2 in Q₂ = A₂V₂ = A₂ 125 100 AP 2 in 25 27 10 9 P2 2(P₁-P₂) √(¹-(3)) 40 1.016 9963.912 5.25312 2 (P₁-P₂) √(¹-(A)) 1- E T(0.0078994m)² ?? ?? ?? ?? (-) - AP= P1-P2 Pa ?? ?? ?? ?? velocity m/s 0.078994m 0.014986m 5.25312m ?? = 49.00925 x 10-6m² ?? ?? ?? flow rate Qori m³/s 0.000257451 2(9963.912)kgm/s² 1000kg/m³(1-(0.277854)²) 3333 ?? = 0.277854 Actual flow rate Qact m³/s 0.000333 0.0003 0.00025 0.000183 0.000117 = 5.25312m/s (49.00925 x 10-6m²) = 0.000257451m³/s The flow rate in this case is lower than the actual flow rate. This is due to the loss in the flow rate caused by the turbulence in the orifice.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: A group of 20 tourists visit san fransico, some ofhe activities they wanted to do sare shown in the…

A: Solution.

Q: How did you work out acceleration and 7+(-3.924) (finding time) is not 1.78

A: Given data:- mass of box (m) =50kg the coefficient of kinetic friction (μ) =0.4 initial velocity of…

Q: I need help with this before tomorrow’s exam if I can get all needed calculations please

A: Step 1: Given Data:Outdoor air temperature: 32° CIndoor air temperature: 18° CCooling load of the…

Q: Experiment 1: The atmosphere a) Calculate the mass of air in a typical classroom (50 feet long, 30…

Q: Problem 6: The top wall moves with velocity Vtop = 1" and the bottom wall is m S stationary. Inside…

A: VISCOSITY is defined as internal resistance offered by one layer of the fluid to the adjacent layer…

Q: Question 2 (35 marks): A company has a project to complete. To complete the project, the following…

A: To draw the Project Diagram/Network (15 pts) and develop a Linear Program (20 pts) for computing the…

Q: Learning Goal: When a body subjected to a couple moment, M, undergoes general planar motion, the two…

A: A pair is made up of two equal and opposite parallel forces acting on a rigid body at distinct…

Q: 1) 20N/m 60 N/m 4 m 2 m 2)

Q: Q)land development company is considering the purchase of earth-moving equipment. This equipment…

A: Given dataOption A - Purchasing the equipmentEstimated first cost of purchase = $163,000Maintenance…

Q: Need help

A: To find the total resultant force exerted on the anchor on the wall, we need to determine the force…

Q: A nationwide hotel chain is considering locating a new hotel in Bigtown, USA. The cost of building a…

A: Given:To find:

Q: 2. Calculate personnel costs of your present method with a proposed method. The current method has a…

A: Given:The current method has a unit value of The proposed method has a unit value of The test volume…

Q: 200 mm - 200 mm 150 mm 125 mm 60 mm 125 mm The top view of the plate thickness is 2 mm. The sheet is…

A: GIVEN :- A top view of plate.thickness : t=2mmdensity of circular part : ρc=4g/cm3density of rest of…

Q: echanical Engineering cable is 5000 m long eighs 49kg/m has a diameter of 133 mm nd a maximum…

Concept explainers

Fluid Dynamics

The study of the flow of gases and liquids, usually in and around solid surfaces, is known as fluid dynamics in physics and engineering. Fluid dynamics, for example, can be used to evaluate the movement of air through an airplane wing or the surface of a vehicle. It can also be used in ship design to increase the speed at which ships pass through water.

Question

i need help with the calculations. i am messing up something in the math

Orifice Meter
From the theory, the equation governing the flow rate through a orifice meter is shown as follows:
The data obtained for orifice meter from the experiment is summarized as follows
ΔΡ
No.
units
Then,
1
2
3
4
5
Flow rate (gpm)
Gallons Per Minute
5
45
4
3
2
Sample Calculations
Inner diameter of the tube = 0.590/n = 0.014986m
Q₂
Orifice Bore = 0.311in = 0.078994m.
A₂ =
in
V₂ =
70
32
MD₂²
Q₂ = A₂V₂ CA₂
C-F
in
200 160
150 125 25
127 100 27
= A₂V₂ = A₂
60
P1-
P2
23
in
10
9
2(P₁-P₂)
√(¹-())
40 1.016 9963.912
??
??
2(P₁-P₂)
√(1-3))
2(P₁-P₂)
√(1-3))
AP=
P1-
P2
T(0.0078994m)²
4
=
m
??
??
(2)-(-
AP=
P1-P2
Pa
??
??
??
??
velocity
0.078994m
0.014986m
m/s
5.25312
??
??
??
= 49.00925 x 10-6m²
??
flow rate
Qori
m³/s
0.000257451
2(9963.912)kgm/s²
1000kg/m³(1-(0.277854)²)
??
??
??
??
= 0.277854
Actual
flow rate
Got
m³/s
0.000333
0.0003
0.00025
0.000183
0.000117
= 5.25312m/s
(5.25312m (49.00925 x 10-6m²) = 0.000257451m²/s
The flow rate in this case is lower than the actual flow rate. This is due to the loss in the flow rate caused by the turbulence in the orifice.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given

VIEW

Step 2: Calculation of flow rate

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 8 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

A dust particle is suspended in the air (floating due to a small updraft and its own low mass) when a powerful loudspeaker plays a very low note (2 Hz so it can’t be heard but you can actually see the speaker move!). How will the dust particle move as a result of the speaker  being turned on? Question 3 options: A) The dust particle will move up and down. B) The dust particle will be pushed across the room. C) The dust particle will move in a circular path. D) The dust particle will move side to side.
A suspended date that's able to pivot from the top seperates two liquids. There is a stopper that prevents the gate opening anti-clockwise. The gate has a height of 0.5m. The liquid on the right is twice as dense as the liquid on the left. The liquid on the left has a depth of 0.3m. 1) What is the minimum depth of liquid on the right for the gate to open. 2) Comment on the ability to solve this question if the liquid on the left was 1m (filled to the top)
Please do this carefully.
A tall building has a shadow of 100m on ground. An engineer used a meterstick to measure the building height indirectly. Using another meterstick, the shadow of the first stick was measured as 0.5m Find the building height.
Don't need to show work, just need to know which ones correct to compare my answers. 7.8.
Grams to Moles Assuming you have enough other parts, how many cars can you make if you have 6 steering wheels?
An electric hot water heater consumes 3.1 kilowatts of electricity and converts it to heat. How long will it take the water heater to heat a 67 gallon tank of water from 10 degrees Celsius to 50 degrees Celsius? (1 kilogram of water is 0.37 gallons, 1 Calorie = 4200 J). It may be helpful to refer back to the weekly handout for guidance on this problem. Your final answer should be in minutes (rounded to the nearest 10 minutes).
You are designing a solar panel cover to protect rooftop solar panels from beingdamaged by debris. At some point during the day, the panels form a 60-degree angle relative to the sun’s rays. The panels are 3m x 1m wide. a) What property of incident radiation do you want to maximize to allow the maximize amount of light to hit the panels below your cover? b) If the absorptivity is 0.2 and the reflectivity is 0.1, what percentage of the radiation reaches the solar panels? c) If the irradiation, G, is 220 W/m2, how much power passes into the solar panels below the cover?