From the table of available reagents, select the one(s) you would use to carry out the following transformation.онCH;CH2CH2CH2C=CHCH3CH2CH2CH,ĊHCH2OCH3Use the minimum number of steps; in no case are more than four steps necessary.List reagents by letter in the order that they are used; example: fa.Reagents availableа. ВНз, ТHF; then H,02. ОНe. HI, H20j. PB13b. Br2f. H2, Lindlar catalystk.-CO,Hc. Hg(OCOCF3)2, CH3CH2OH;then NABH4g. NaHh. ОН, Н-оd. Hg(OCOCF3)2, CH;OH;then NaBH4I. CH3Ii. "OCH3, CH3OH

This is oxymercuration reaction.

Answered: From the table of available reagents,…

From the table of available reagents, select the one(s) you would use to carry out the following transformation. он ?. CH;CH2CH2CH2C=CH CH;CH2CH2CH2ČHCH2OCH3

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Reactions at the Alpha Carbon Atom

The position next to the ketone or aldehyde functional group is termed as alpha position and the reaction which occurs at alpha position is called alpha substitution reaction. In an alpha substitution reaction, the alpha proton atom is substituted by an electrophile by the formation of an enol intermediate or enolate ion intermediate. Most of the carbonyl compounds go through an alpha substitution reaction.

Question

From the table of available reagents, select the one(s) you would use to carry out the following transformation.
он
CH;CH2CH2CH2C=CH
CH3CH2CH2CH,ĊHCH2OCH3
Use the minimum number of steps; in no case are more than four steps necessary.
List reagents by letter in the order that they are used; example: fa.
Reagents available
а. ВНз, ТHF; then H,02. ОН
e. HI, H20
j. PB13
b. Br2
f. H2, Lindlar catalyst
k.
-CO,H
c. Hg(OCOCF3)2, CH3CH2OH;
then NABH4
g. NaH
h. ОН, Н-о
d. Hg(OCOCF3)2, CH;OH;
then NaBH4
I. CH3I
i. "OCH3, CH3OH

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