From the following list of aqueous solutions and water: Select the one with the highest boiling point. Select the one with the lowest freezing point. A. 1.0 m KNO3 B. 0.75 m NaCl C. 0.75 m CuCl₂ D. 2.0 m C12H22O11 (sucrose) E. pure water Determine the freezing point of a solution that contains 0.31 mol of sucrose in 175 g of water, where K₁ = 1.86°C/m. A. 3.3°C Your answer: B. 1.1°C C. 0.0°C D. -1.1°C E. -3.3°C

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### Study of Aqueous Solutions and Freezing Point Determination

#### 1. Boiling Point and Freezing Point of Aqueous Solutions

From the following list of **aqueous solutions and water**:

- **Select the one with the highest boiling point.**
- **Select the one with the lowest freezing point.**

| Aqueous Solutions     | Options             |
|-----------|--------------------|
| **A**     | 1.0 m KNO₃         |
| **B**     | 0.75 m NaCl        |
| **C**     | 0.75 m CuCl₂       |
| **D**     | 2.0 m C₁₂H₂₂O₁₁ (sucrose) |
| **E**     | pure water         |

#### 2. Calculation of Freezing Point Depression

Determine the freezing point of a solution that contains 0.31 mol of sucrose in 175 g of water. The freezing point depression constant \( K_f \) is 1.86°C/m.

Options for freezing point:
- **A. 3.3°C**
- **B. 1.1°C**
- **C. 0.0°C**
- **D. –1.1°C**
- **E. –3.3°C**

**Your answer: [ ]

In the solution provided, the freezing point depression (\( \Delta T_f \)) can be calculated using the formula:
\[ \Delta T_f = K_f \times m \]
where \( m \) is the molality of the solution.

#### Explanation Diagrams and Graphs

There are no specific diagrams or graphs provided in this question. The problems focus on understanding colligative properties and calculating the freezing point depression for a given molal concentration.

This educational content is designed to enhance the understanding of colligative properties of solutions, particularly boiling point elevation and freezing point depression, which are fundamental concepts in physical chemistry.
Transcribed Image Text:### Study of Aqueous Solutions and Freezing Point Determination #### 1. Boiling Point and Freezing Point of Aqueous Solutions From the following list of **aqueous solutions and water**: - **Select the one with the highest boiling point.** - **Select the one with the lowest freezing point.** | Aqueous Solutions | Options | |-----------|--------------------| | **A** | 1.0 m KNO₃ | | **B** | 0.75 m NaCl | | **C** | 0.75 m CuCl₂ | | **D** | 2.0 m C₁₂H₂₂O₁₁ (sucrose) | | **E** | pure water | #### 2. Calculation of Freezing Point Depression Determine the freezing point of a solution that contains 0.31 mol of sucrose in 175 g of water. The freezing point depression constant \( K_f \) is 1.86°C/m. Options for freezing point: - **A. 3.3°C** - **B. 1.1°C** - **C. 0.0°C** - **D. –1.1°C** - **E. –3.3°C** **Your answer: [ ] In the solution provided, the freezing point depression (\( \Delta T_f \)) can be calculated using the formula: \[ \Delta T_f = K_f \times m \] where \( m \) is the molality of the solution. #### Explanation Diagrams and Graphs There are no specific diagrams or graphs provided in this question. The problems focus on understanding colligative properties and calculating the freezing point depression for a given molal concentration. This educational content is designed to enhance the understanding of colligative properties of solutions, particularly boiling point elevation and freezing point depression, which are fundamental concepts in physical chemistry.
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