From previous studies, it is concluded that 90% of phone numbers in a certain city are unlisted. A researcher claims that the proportion is smaller than 90% and decides to survey 800 working adults. Test the researcher’s claim at the \( \alpha = 0.01 \) significance level.**Preliminary:**a. Is it safe to assume that \( n \leq 0.05 \) of all subjects in the population?- [ ] Yes- [ ] Nob. Verify \( np(1 - p) \geq 10 \). Round your answer to one decimal place.\[ np(1 - p) = \underline{\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad} \]**Test the claim:**a. The null and alternative hypotheses are:- [ ] \( H_0: \mu = 0.9 \) \( H_a: \mu \neq 0.9 \) - [ ] \( H_0: \mu \geq 0.9 \) \( H_a: \mu < 0.9 \)- [ ] \( H_0: \mu \leq 0.9 \) \( H_a: \mu > 0.9 \)- [ ] \( H_0: p = 0.9 \) \( H_a: p \neq 0.9 \)- [ ] \( H_0: p \geq 0.9 \) \( H_a: p < 0.9 \)- [ ] \( H_0: p \leq 0.9 \) \( H_a: p > 0.9 \)b. The test is:- [ Select an answer ]c. Based on the sample of 800 people, 81% phone numbers in a certain city are unlisted. What is the test statistic? Round your answer to two decimal places.\[ \underline{\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad} \]d. What is the p-value? Round your answer to four decimal places.\[ \underline{\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad} \]e. Make a decision.- [

Name: From previous studies, it is concluded that 90% of phone numbers in a
Uploaded: 2024-03-20T07:06:41.000Z
Channel: Bartleby
Description: From previous studies, it is concluded that 90% of phone numbers in a certain city are unlisted. A researcher claims that the proportion is smaller than 90% and decides to survey 800 working adults. Test the researcher’s claim at the \( \alpha = 0.0

Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts. In case you require the unanswered parts also, kindly re-post that parts separately. a) One of the assumption for testing the population proportion is nN≤0.05n≤0.05NHere, n: sample sizeN: population size Yes, It is safe to assume that n≤0.05 of all subjects in the population.b) Given p=90%=0.90 n=800 Consider, np(1-p)=800*0.90*(1-0.90) =72≥10 np(1-p)=72.0 rounded to one decimal place. a. Claim: Population proportion is smaller than 90% Null Hypothesis: Ho: p>=0.9 Alternative Hypothesis: H1: p<0.90. Correct option:

Math

Statistics

From previous studies, it is concluded that 90% of phone numbers in a certain city are unlisted. A researcher claims that the proportion is smaller than 90% and decides to survey 800 working adults. the researcher's claim at the a = 0.01 significance level. Preliminary: a. Is it safe to assume that n< 0.05 of all subjects in the population? Yes No

From previous studies, it is concluded that 90% of phone numbers in a certain city are unlisted. A researcher claims that the proportion is smaller than 90% and decides to survey 800 working adults. the researcher's claim at the a = 0.01 significance level. Preliminary: a. Is it safe to assume that n< 0.05 of all subjects in the population? Yes No

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A concerned group of citizens wanted to determine whether the proportion of armed robberies in the state of Texas was different in 2011 than in 2010. Research shows that of the 113,231 violent crimes in Texas in 2010, 7,622 of them were armed robberies. In 2011, 7,439 of the 104,873 violent crimes were in the armed robery category. Test at the 0.05 significance level. Preliminary: a. Is it safe to assume that n2010 < 5% of all violent crimes during 2010 and n2011 5% of all violent crimes during 2011? O Yes ONo b. Verify np(1-P)2 10. Round your answer to one decimal place. n12010p (1 – p) = N2011P(1 – p) = Test the claim: a. Determine the null and alternative hypotheses. Ho: P2010 ? VP2011 H.: P2010 ? V P2011 b. Determine the test statistic. Round to two decimal places. c. Find the p-value. Round to four decimals. P-value = d. Make a decision. O Reject the null hypothesis. O Fail to reject the null hypothesis. e. Write the conclusion. OThere is not sufficient evidence to support the…
1. Ten subjects were chosen for an experiment. They were asked to perform a certain physical activity. The number of heartbeats per minute, before and after experiment are recorded as follows: Subject Before After Subject Before After number number 1 60 92 72 76 2 67 79 7 71 73 72 72 8 69 81 4 71 80 75 80 68 72 10 68 76 Is there sufficient evidence to indicate that the experiment condition increases the number of heartbeats per minute? Use a .05 level of significance.
In a random sample of 925 plain M&M's, 19% were blue. Use a 0.01 significance level to test the claim of Mars, Inc. that 24% of its plain M&M candies are blue. a. Define the parameter A. p = The proportion of all M&M's that are blue B. mu = The proportion of all M&M's that are blue C. mu = The mean number of all M&M's that are blue D. p = The proportion of all M&M's that are not blue b. State the null and alternative hypotheses A. Upper H 0 : p greater than 0.24 Upper H 1 : p equals 0.24 B. Upper H 0 : p equals 0.19 Upper H 1 : p not equals 0.19 C. Upper H 0 : p equals 0.24 Upper H 1 : p not equals 0.24 D. Upper H 0 : mu not equals 0.24 Upper H 1 : mu equals 0.24 c. Calculate the test statistic. Which of these options is closest to the test statistic? A. negative 4.00 B. negative 3.65 C.…
Suppose that in a random selection of 100100 colored candies, 2323% of them are blue. The candy company claims that the percentage of blue candies is equal to 2525%. Use a 0.100.10 significance level to test that claim.
A company claims that at least 94% of equipment supplied to a manufacturer is within specifications. A test of a sample of 200 pieces of equipment showed that 27 of them were faulty. Test their claim at the 5% significance level?
1. A researcher uses a one-sample t-test to test a sample mean based on 27 scores against a hypothesized population mean. What is the degrees of freedom for this t-test? A. 26 B. 28 C. 29 D. 27 2. If a researcher takes a large enough sample, he/she will almost always obtain: A. consequentially significant results B. virtually significant results C. practically significant results D. statistically significant results
Suppose that in a random selection of 100 colored candies, 25% of them are blue. The candy company claims that the percentage of blue candies is equal to 22%. Use a 0.05 significance level to test that claim. O A. Ho p=0.22 Hy p>0.22 O B. Ho p=0.22 H p 0 22 O C. Ho pt0.22 H p=022 O D. Ho p=0.22 H1 p<0.22 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed ) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is | (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Fail to reject Ho. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 22% O B. Reject Hn. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 22% OC. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that the…
A barangay captain claims that at least 25% of the residents in his barangay have household pets. To test this claim a researcher randomly selected a sample of 50 residents and find that 13 of them do have pets. What can you conclude at 0.10 level of significance.
b. In 2018, a sample of 300 in-store shoppers showed that 44 paid by debit card. The results shown in the table below were obtained when a sample of 400 in-store shoppers were surveyed in 2019. Year 2018 2019 Shoppers Surveyed Shoppers Paying by Debit Card 44 Formulate appropriate hypotheses to test whether the percentage of debit card shoppers increased, and conduct the test using a significance level of 0.01. What is your conclusion? 300 400