Initially, a warehouse worker pushes a 55 [N] box on a flat, rough, horizontal surface just enough so that the box moves with a constant velocity of 4.2 [m/s]. However, he gets tired and suddenly stops pushing the box. With the coefficient of kinetic friction between the box and the surface equal to 0.45, how long does it take for the box to stop? A. 0.95 [s] B. 2.1 [s] C. 4.4 [s] D. 9.3 [s

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Chapter1: Units, Trigonometry. And Vectors
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Initially, a warehouse worker pushes a 55 [N] box on a flat, rough, horizontal surface just enough so that the box moves with a constant velocity of 4.2 [m/s].
However, he gets tired and suddenly stops pushing the box. With the coefficient of kinetic
friction between the box and the surface equal to 0.45, how long does it take for the box to
stop?

A. 0.95 [s]
B. 2.1 [s]
C. 4.4 [s]
D. 9.3 [s

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"from kinematic equations of motion,

vf=v0+att=vf-v0a=(0-4.2) m/s-4.41 m/s2=0.95 st=0.95 s

conclusion:

answer is option A which is 0.95 s"

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