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X GRA QUESTION 28 One end of a 1.0 m long string is fixed; the other end is attached to a 2.0 kg stone. The stone swings in a vertical circle, passing the bottom point at 4. m/s. The tension force of the string at this point is about: OA. 52 N OB. 20 N OC. 32 N OD. 12 N ΟΕΟΝ xis changes from vi to vf. For which values of v; and vy is the total work done on the pa

X GRA QUESTION 28 One end of a 1.0 m long string is fixed; the other end is attached to a 2.0 kg stone. The stone swings in a vertical circle, passing the bottom point at 4. m/s. The tension force of the string at this point is about: OA. 52 N OB. 20 N OC. 32 N OD. 12 N ΟΕΟΝ xis changes from vi to vf. For which values of v; and vy is the total work done on the pa

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Physics Exam Sample Questions** --- **QUESTION 28** *One end of a 1.0 m long string is fixed, the other end is attached to a 2.0 kg stone. The stone swings in a vertical circle, passing the bottom point at 4.0 m/s. The tension force of the string at this point is about:* - **A.** 52 N - **B.** 20 N - **C.** 32 N - **D.** 12 N - **E.** 0 N --- **QUESTION 29** *The velocity of a particle moving along the x-axis changes from Vi to Vf. For which values of Vi and Vf is the total work done on the particle zero?* - **A.** Vi = 5 m/s, Vf = -2 m/s - **B.** Vi = -2 m/s, Vf = 2 m/s - **C.** Vi = 5 m/s, Vf = 2 m/s - **D.** Vi = 5 m/s, Vf = -5 m/s - **E.** Vi = 5 m/s, Vf = 2 m/s 1. Select the correct answer for each question. 2. Click 'Save All Answers' to save and submit. --- **Note:** There are no diagrams or graphs accompanying these questions.
Transcribed Image Text:**Physics Exam Sample Questions** --- **QUESTION 28** *One end of a 1.0 m long string is fixed, the other end is attached to a 2.0 kg stone. The stone swings in a vertical circle, passing the bottom point at 4.0 m/s. The tension force of the string at this point is about:* - **A.** 52 N - **B.** 20 N - **C.** 32 N - **D.** 12 N - **E.** 0 N --- **QUESTION 29** *The velocity of a particle moving along the x-axis changes from Vi to Vf. For which values of Vi and Vf is the total work done on the particle zero?* - **A.** Vi = 5 m/s, Vf = -2 m/s - **B.** Vi = -2 m/s, Vf = 2 m/s - **C.** Vi = 5 m/s, Vf = 2 m/s - **D.** Vi = 5 m/s, Vf = -5 m/s - **E.** Vi = 5 m/s, Vf = 2 m/s 1. Select the correct answer for each question. 2. Click 'Save All Answers' to save and submit. --- **Note:** There are no diagrams or graphs accompanying these questions.
### Physics Problem-Solving Exercise #### QUESTION 29: The velocity of a particle moving along the x-axis changes from vi to vf. For which values of vi and vf is the total work done on the particle positive? - **A.** vi = -5 m/s, vf = 2 m/s - **B.** vi = -2 m/s, vf = -2 m/s - **C.** vi = 5 m/s, vf = -5 m/s - **D.** vi = 5 m/s, vf = 2 m/s - **E.** vi = 5 m/s, vf = -2 m/s #### QUESTION 30: A spring of spring constant k is attached to a block of mass m. The spring moves the block through a displacement x. How can you calculate the work done on the block? - **A.** Multiply the spring force, \(\frac{1}{2} k x^2\), by the distance x - **B.** Integrate the spring force, \(\frac{1}{2} k x^2\), over the time it takes the block to move - **C.** Multiply the spring force, kx, by the distance x - **D.** Integrate the spring force, kx, over the distance x - **E.** We cannot calculate this without knowing the acceleration of the block Study these questions carefully and choose the best answer from the options provided. To succeed in this exercise, consider the principles of work and energy, and the characteristics of spring forces.
Transcribed Image Text:### Physics Problem-Solving Exercise #### QUESTION 29: The velocity of a particle moving along the x-axis changes from vi to vf. For which values of vi and vf is the total work done on the particle positive? - **A.** vi = -5 m/s, vf = 2 m/s - **B.** vi = -2 m/s, vf = -2 m/s - **C.** vi = 5 m/s, vf = -5 m/s - **D.** vi = 5 m/s, vf = 2 m/s - **E.** vi = 5 m/s, vf = -2 m/s #### QUESTION 30: A spring of spring constant k is attached to a block of mass m. The spring moves the block through a displacement x. How can you calculate the work done on the block? - **A.** Multiply the spring force, \(\frac{1}{2} k x^2\), by the distance x - **B.** Integrate the spring force, \(\frac{1}{2} k x^2\), over the time it takes the block to move - **C.** Multiply the spring force, kx, by the distance x - **D.** Integrate the spring force, kx, over the distance x - **E.** We cannot calculate this without knowing the acceleration of the block Study these questions carefully and choose the best answer from the options provided. To succeed in this exercise, consider the principles of work and energy, and the characteristics of spring forces.
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