Packages enter the 12.9-ft chute at A with a speed of 5.0 ft/sec and have a 0.41g acceleration from A to B. If the packages come to rest at C, calculate the constant acceleration a (positive if it speeds up, negative if it slows down) of the packages from B to C. Also find the time required for the packages to go from A to C. 12.9' Answers: From B to C, a= From A to C, t= B i i 15.5' ft/sec² sec

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Chapter1: Units, Trigonometry. And Vectors
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Packages enter the 12.9-ft chute at A with a speed of 5.0 ft/sec and have a 0.41g acceleration from
A to B. If the packages come to rest at C, calculate the constant acceleration a (positive if it speeds
up, negative if it slows down) of the packages from B to C. Also find the time required for the
packages to go from A to C.
12.9'
Answers:
From B to C, a=
From A to C, t=
B
i
i
15.5'-
O
ft/sec²
sec
Transcribed Image Text:Packages enter the 12.9-ft chute at A with a speed of 5.0 ft/sec and have a 0.41g acceleration from A to B. If the packages come to rest at C, calculate the constant acceleration a (positive if it speeds up, negative if it slows down) of the packages from B to C. Also find the time required for the packages to go from A to C. 12.9' Answers: From B to C, a= From A to C, t= B i i 15.5'- O ft/sec² sec
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Follow-up Question
Packages enter the 12.9-ft chute at A with a speed of 5.0 ft/sec and have a 0.41g acceleration from
A to B. If the packages come to rest at C, calculate the constant acceleration a (positive if it speeds
up, negative if it slows down) of the packages from B to C. Also find the time required for the
packages to go from A to C.
12.9'
Answers:
From B to C, a=
From A to C, t =
B1
B
-11.78
-15.5'-
i 2.72
ft/sec²
sec
Transcribed Image Text:Packages enter the 12.9-ft chute at A with a speed of 5.0 ft/sec and have a 0.41g acceleration from A to B. If the packages come to rest at C, calculate the constant acceleration a (positive if it speeds up, negative if it slows down) of the packages from B to C. Also find the time required for the packages to go from A to C. 12.9' Answers: From B to C, a= From A to C, t = B1 B -11.78 -15.5'- i 2.72 ft/sec² sec
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