From a solar observation fieldwork, the sun’s corrected altitude was determined to be 34°20’ and the declination was 25°10’. If the observer is at latitude 50°13’, compute for the apparent time of the place and the azimuth from the South of the sun.
From a solar observation fieldwork, the sun’s corrected altitude was determined to be 34°20’ and the declination was 25°10’. If the observer is at latitude 50°13’, compute for the apparent time of the place and the azimuth from the South of the sun.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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From a solar observation fieldwork, the sun’s corrected altitude was determined to be 34°20’ and the declination was 25°10’. If the observer is at latitude 50°13’, compute for the apparent time of the place and the azimuth from the South of the sun.
Use the following formulas based from the PZS triangle.
Transcribed Image Text:| cot 4=sec S see(S – P)sin (S – H)sin (S - L)
If the abservation was made in the morning, the azimuth of the
sun is equal to 360° - A. If the observation was made in the
afternoon, the azimuth of the sun is equal to A.
![cos (t) = [ sin (H) – sin (4) sin (6) ]/[ cos (4) cos (õ) ]
where: t= 24-h or h, hour angle](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F481bc899-0797-4561-9324-e9cc6f62088a%2F12d8a895-5aa3-49cb-91fb-b938436fd66d%2Fikbkxzp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:cos (t) = [ sin (H) – sin (4) sin (6) ]/[ cos (4) cos (õ) ]
where: t= 24-h or h, hour angle
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