From a large number of actuarial exam scores, a random sample of 250 scores is selected, and it is found that 182 of these 250 are passing scores. Based on this sample, find a 95% confidence interval for the proportion of all scores that are passing. Then find the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.) Lower limit: U ? Upper limit: 0
From a large number of actuarial exam scores, a random sample of 250 scores is selected, and it is found that 182 of these 250 are passing scores. Based on this sample, find a 95% confidence interval for the proportion of all scores that are passing. Then find the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.) Lower limit: U ? Upper limit: 0
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.
- **Lower limit:** [input box]
- **Upper limit:** [input box]
### Instructions:
1. Calculate the sample proportion (p̂) of passing scores.
2. Determine the standard error (SE) for the proportion.
3. Use the Z-value for the 95% confidence interval.
4. Calculate the lower limit and upper limit for the confidence interval.
### Example Calculation:
1. Sample proportion (p̂) = Number of passing scores / Total number of scores = 182 / 250.
2. Standard Error (SE) = sqrt[(p̂(1 - p̂)) / n], where n is the sample size.
3. Apply the 95% confidence level (Z-value ≈ 1.96).
4. Compute the confidence interval as follows:
- Lower limit = p̂ - (Z-value * SE)
- Upper limit = p̂ + (Z-value * SE)
Enter your final answers rounded to two decimal places. Use the provided input boxes to record your results.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8441b9ff-a8cf-4673-aa83-a1fcebb34e98%2Ff8916899-0d4d-48b6-b3fa-a1e6f22fcf21%2Fd7jo9p_processed.png&w=3840&q=75)
Transcribed Image Text:### Confidence Interval for Proportion of Passing Scores
From a large number of actuarial exam scores, a random sample of 250 scores is selected, and it is found that 182 of these 250 are passing scores. Based on this sample, find a 95% confidence interval for the proportion of all scores that are passing. Then find the lower limit and upper limit of the 95% confidence interval.
Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a [list of formulas](#).
- **Lower limit:** [input box]
- **Upper limit:** [input box]
### Instructions:
1. Calculate the sample proportion (p̂) of passing scores.
2. Determine the standard error (SE) for the proportion.
3. Use the Z-value for the 95% confidence interval.
4. Calculate the lower limit and upper limit for the confidence interval.
### Example Calculation:
1. Sample proportion (p̂) = Number of passing scores / Total number of scores = 182 / 250.
2. Standard Error (SE) = sqrt[(p̂(1 - p̂)) / n], where n is the sample size.
3. Apply the 95% confidence level (Z-value ≈ 1.96).
4. Compute the confidence interval as follows:
- Lower limit = p̂ - (Z-value * SE)
- Upper limit = p̂ + (Z-value * SE)
Enter your final answers rounded to two decimal places. Use the provided input boxes to record your results.
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