frictionless 30° incline. This block is connected to Block 2 (m2 = 22.0 kg) by a massless cord passess over a massless and frictionless pulley. Find the acceleration of each block and the m2 tension in the cord. 30° A 25.0-kg object is suspended from a surface by string. Find the tension on the strings.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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1.
Block 1 (m, = 8.00 kg) is moving on a
frictionless 30° incline. This block is connected
to Block 2 (m2 = 22.0 kg) by a massless cord
passess over a massless and frictionless pulley.
Find the acceleration of each block and the
m2
tension in the cord.
30°
2.
A 25.0-kg object is suspended from a surface
by string. Find the tension on the strings.
Express your answers to two decimal places.
45°
T2
30
T1
3.
Two people are pushing a stalled car. The mass
of the car is 1850 kg. One person applies a force
of 275 N to the car, while the other applies a
275 N
force of 395 N. Both forces acts in the same
direction. A third force of 560 N also acts on
395 N
the car but in a direction opposite to that in
which the people are pushing. This force arises
because of friction and the extent to which the
Opposing force = 560 N
pavement opposes the motion of the tires. Find
the acceleration of the car.
(a)
Transcribed Image Text:1. Block 1 (m, = 8.00 kg) is moving on a frictionless 30° incline. This block is connected to Block 2 (m2 = 22.0 kg) by a massless cord passess over a massless and frictionless pulley. Find the acceleration of each block and the m2 tension in the cord. 30° 2. A 25.0-kg object is suspended from a surface by string. Find the tension on the strings. Express your answers to two decimal places. 45° T2 30 T1 3. Two people are pushing a stalled car. The mass of the car is 1850 kg. One person applies a force of 275 N to the car, while the other applies a 275 N force of 395 N. Both forces acts in the same direction. A third force of 560 N also acts on 395 N the car but in a direction opposite to that in which the people are pushing. This force arises because of friction and the extent to which the Opposing force = 560 N pavement opposes the motion of the tires. Find the acceleration of the car. (a)
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