Friction factor, which is the resistance to flow in such conduits is parameterized by a dimensionless number. It plays a vital role in determining fluid flow through pipes and tubes in many areas of engineering and science. In engineering, typical applications include the flow of liquids and gases through pipelines and cooling systems. In a turbulent flow, the Colebrook equation provides a means to calculate the friction factor: 1 0 = =+ 2log(- 2.51 + 3.7D ' Reyf Where, f = friction factor, e = roughness (m), D = diameter (m), and Re = Reynolds number: pVD Re =

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Where p = fluid's density (kg/m³), V = velocity (m/s) and µ = dynamic viscosity (N-s/m²).
In addition, the Reynolds number also serves as the criterion for whether flow is
turbulent (Re > 4000).
Using any numerical root-finding method, determine the friction factor for air flow
through a smooth, thin tube. For this case, the parameters are given. Note that friction
factors range from about 0.008 to 0.08. Report all your answers accurate to 3 decimal
places. Use a tolerance of 10-6.
p = 1.23 kg/m³ ,µ = 1.79x10-5 Ns/m², D = 0.005 m, V = 40 m/s, and e = 0.0015 mm
Transcribed Image Text:Where p = fluid's density (kg/m³), V = velocity (m/s) and µ = dynamic viscosity (N-s/m²). In addition, the Reynolds number also serves as the criterion for whether flow is turbulent (Re > 4000). Using any numerical root-finding method, determine the friction factor for air flow through a smooth, thin tube. For this case, the parameters are given. Note that friction factors range from about 0.008 to 0.08. Report all your answers accurate to 3 decimal places. Use a tolerance of 10-6. p = 1.23 kg/m³ ,µ = 1.79x10-5 Ns/m², D = 0.005 m, V = 40 m/s, and e = 0.0015 mm
Problem 5
Friction factor, which is the resistance to flow in such conduits is parameterized by a
dimensionless number. It plays a vital role in determining fluid flow through pipes and
tubes in many areas of engineering and science. In engineering, typical applications
include the flow of liquids and gases through pipelines and cooling systems.
In a turbulent flow, the Colebrook equation provides a means to calculate the friction
factor:
2.51
1
+ 2log(-
3.7D ' Reyf
e
0 = -
Where, f = friction factor, e = roughness (m), D = diameter (m), and Re = Reynolds
number:
pVD
Re =
Transcribed Image Text:Problem 5 Friction factor, which is the resistance to flow in such conduits is parameterized by a dimensionless number. It plays a vital role in determining fluid flow through pipes and tubes in many areas of engineering and science. In engineering, typical applications include the flow of liquids and gases through pipelines and cooling systems. In a turbulent flow, the Colebrook equation provides a means to calculate the friction factor: 2.51 1 + 2log(- 3.7D ' Reyf e 0 = - Where, f = friction factor, e = roughness (m), D = diameter (m), and Re = Reynolds number: pVD Re =
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