Free dessert: In an attempt to increase business on Monday nights, a restaurant offers a free dessert with every dinner order.Before the offer, the mean number of dinner customers on Monday was 150. Following are the numbers of diners on a randomsample of 12 days while the offer was in effect. Can you conclude that the mean number of dinners decreased while the freedessert offer was in effect? Use the a = 0.05 level of significance and the P-value method with the TI-84 Plus calculator. 175138160 121181108111120143 189161122Following is a boxplot for these data. Is it reasonable to assume that the conditions for performing a hypothesis test aresatisfied? Explain.100120140160180200220240The boxplot shows that there (Choose one)outliers.areThe boxplot shows that there are noevidence of strong skewness.We (Choose one)assume that the population is approximately normal.It (Choose one) v reasonable to assume that the conditions are satisfled.The boxplot shows that there (Choose one) outliers.The boxplot shows that there (Choose one)evidence of strong skewness.We (Choose one)assume that the population is approximately normal.canIt dcannotJeasonable to assume that the conditions are satisfied.The boxplot shows that there (Choose one) outliers.The boxplot shows that there (Choose one) evidence of strong skewness.We (Choose one) assume that the population is approximately normal.It (Choose one) reasonable to assume that the conditions are satisfled.isis notThe boxplot shows that there (Choose one) outliers.The boxplot shows that there (Choose one) evidence of strong skewness.We (Choose one) assume is nopn is approximately normal.It (Choose one) reasonable to assume that the conditions are satisfied. Part 1 of 4State the appropriate null and alternate hypotheses.HoThis hypothesis test is a (Choose one) v test.left-tailedright-talledtwo-tailedPart 2 of 4Compute the P-value. Round the P-value to at least four decimal places.P-value =Part 3 of 4Determine whether to reject H(Choose one)the null hypothesis H.RejectDo not reject

Answered: Free dessert: In an attempt to increase…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Free dessert: In an attempt to increase business on Monday nights, a restaurant offers a free dessert with every dinner order. Before the offer, the mean number of dinner customers on Monday was 150. Following are the numbers of diners on a random sample of 12 days while the offer was in effect. Can you conclude that the mean number of dinners decreased while the free dessert offer was in effect? Use the a = 0.05 level of significance and the P-value method with the TI-84 Plus calculator.

175
138
160 121
181
108
111
120
143 189
161
122
Following is a boxplot for these data. Is it reasonable to assume that the conditions for performing a hypothesis test are
satisfied? Explain.
100
120
140
160
180
200
220
240
The boxplot shows that there (Choose one)
outliers.
are
The boxplot shows that there are no
evidence of strong skewness.
We (Choose one)
assume that the population is approximately normal.
It (Choose one) v reasonable to assume that the conditions are satisfled.
The boxplot shows that there (Choose one) outliers.
The boxplot shows that there (Choose one)
evidence of strong skewness.
We (Choose one)
assume that the population is approximately normal.
can
It dcannot
Jeasonable to assume that the conditions are satisfied.
The boxplot shows that there (Choose one) outliers.
The boxplot shows that there (Choose one) evidence of strong skewness.
We (Choose one) assume that the population is approximately normal.
It (Choose one) reasonable to assume that the conditions are satisfled.
is
is not
The boxplot shows that there (Choose one) outliers.
The boxplot shows that there (Choose one) evidence of strong skewness.
We (Choose one) assume is no
pn is approximately normal.
It (Choose one) reasonable to assume that the conditions are satisfied.

Part 1 of 4
State the appropriate null and alternate hypotheses.
Ho
This hypothesis test is a (Choose one) v test.
left-tailed
right-talled
two-tailed
Part 2 of 4
Compute the P-value. Round the P-value to at least four decimal places.
P-value =
Part 3 of 4
Determine whether to reject H
(Choose one)
the null hypothesis H.
Reject
Do not reject

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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