Suppose that Sandy is an analyst for the bicyling industry and wants to estimate the asking price of used entry-level road bikes advertised online in the southeastern part of the United States. She obtains a random sample of n = 10 online advertisements of entry-level road bikes. She determines that the mean price for these 10 bikes is $659.87 and that the sample standard deviation is s = $197.02. She uses this information to construct a 95% confidence interval for u, the mean price of a used road bike. What is the upper limit of this confidence interval? Please give your answer to the nearest cent. table of t-critical values Answer: 800.9 X

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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THE ANSWER IS NOT 800.9, 800.8, 800.80 or 780.2 or 801. I tried this question numerous times and it's all wrong.

Suppose that Sandy is an analyst for the bicyling industry and wants to
estimate the asking price of used entry-level road bikes advertised online in
the southeastern part of the United States. She obtains a random sample
of n = 10 online advertisements of entry-level road bikes. She determines
that the mean price for these 10 bikes is $659.87 and that the sample
standard deviation is s = $197.02. She uses this information to construct a
95% confidence interval for u, the mean price of a used road bike.
What is the upper limit of this confidence interval? Please give your answer
to the nearest cent.
table of t-critical values
Answer: 800.9
Transcribed Image Text:Suppose that Sandy is an analyst for the bicyling industry and wants to estimate the asking price of used entry-level road bikes advertised online in the southeastern part of the United States. She obtains a random sample of n = 10 online advertisements of entry-level road bikes. She determines that the mean price for these 10 bikes is $659.87 and that the sample standard deviation is s = $197.02. She uses this information to construct a 95% confidence interval for u, the mean price of a used road bike. What is the upper limit of this confidence interval? Please give your answer to the nearest cent. table of t-critical values Answer: 800.9
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