frame shown in Figure a Sketch the free body diagram and calculate the support reactions of the frame. 3 Calculate the support reaction if the load on span AB is changed to triangle non- distributed load with O KN/m at point B. 1 kN/m 1 kN/m B 1.2 m 1.8 m 2 kN/m

Q: For the beam and loading shown in Figure Q2: - a. Determine the support reactions b. Draw the shear…

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Q: Consider the beam shown below. Take P = 5 kip and w = 1.7 kip/ft. Point E is just to the right of…

A: Solution:Given Data:The concentrated load acting on the beam is P=5kipThe intensity of uniformly…

Q: Support reactions will be found in the gerber beam whose loading condition is given in the figure.…

A: B is a sliding joint. Since we know that in a sliding joint there is only one reaction in the…

Q: The 6 m long beam above is subjected to a point force of 15 kN at an angle of θ = 60°, a clockwise…

A: We are authorized to answer three subparts at a time, since you have not mentioned which part you…

Q: 1. Given the beam shown: F L Use F = 50 kN and L = 6 m a. Compute for the support reactions b. Draw…

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Q: 6. Determine the support reactions of the plane frame as shown in Figure 6 (Answer for P=5, Ro=98.25…

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Q: Problem A: The beam shown is part of a walkway of a gymnasium. The beam ABC can be considered simply…

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Q: y 2 kN 4 kN/m A 3 m -1.5 m 1.5 m

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Q: 1. Determine reactions at A and B 2. Draw shear and moment Diagram 3. Find M max location between…

A: Determinea. The support reaction. b. Draw the shear force and moment diagram. c. Location and…

Q: 3) 1.2 k/ft 17 k 450 А 6 ft В 8 ft 18 ft

A: Reactions

Q: 8. For the beam and loading shown, determine the reaction at the roller support. The beam is…

A: Beam: Section: W 250 x 25.3 Load density: wo = 2 kN/m Length of the beam: L = 9 m Young's modulus:…

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.