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four peanut M&M's from an extra-large bag of the candies. Calculate the following probablities, Also calculate the mean and standard deviation of the distribution. Round all solutions to four decimal places, if necessary. Compute the probability that exactly two of the four M&M's are yellow. P(r = 2) = .0669 Compute the probability that two or three of the four M&M's are yellow. P(x = 2 or a = 3) .0730 Compute the probability that at most two of the four M&M's are yellow. P(x < 2) .9937 Compute the probability that at least two of the four M&M's are yellow. P(x > 2) .10282 x %3D If

four peanut M&M's from an extra-large bag of the candies. Calculate the following probablities, Also calculate the mean and standard deviation of the distribution. Round all solutions to four decimal places, if necessary. Compute the probability that exactly two of the four M&M's are yellow. P(r = 2) = .0669 Compute the probability that two or three of the four M&M's are yellow. P(x = 2 or a = 3) .0730 Compute the probability that at most two of the four M&M's are yellow. P(x < 2) .9937 Compute the probability that at least two of the four M&M's are yellow. P(x > 2) .10282 x %3D If

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Can I had assistance with parts D, E, F please
four peanut M&M's from an extra-large bag of the candies. Calculate the following probablities. Also calculate the mean and standard deviation of the distribution. Round all solutions to four decimal places, if necessary. Compute the probability that exactly two of the four M&M's are yellow. P(x = 2) = .0669 Compute the probability that two or three of the four M&M's are yellow. P(x = 2 or x = 3) = .0730 Compute the probability that at most two of the four M&M's are yellow. P(x < 2) = .9937 Compute the probability that at least two of the four M&M's are yellow. P(x > 2) =.10282 x If you repeatedly select random samples of four peanut M&M's, on average how many do you expect to be yellow? .6 x yellow M&M's With what standard deviation? .7266 x yellow M&M's 12 s米 14 f6 17 fe 20 fg %23 & 3. 4. 6. 7. 80 (O LO %24
Transcribed Image Text:four peanut M&M's from an extra-large bag of the candies. Calculate the following probablities. Also calculate the mean and standard deviation of the distribution. Round all solutions to four decimal places, if necessary. Compute the probability that exactly two of the four M&M's are yellow. P(x = 2) = .0669 Compute the probability that two or three of the four M&M's are yellow. P(x = 2 or x = 3) = .0730 Compute the probability that at most two of the four M&M's are yellow. P(x < 2) = .9937 Compute the probability that at least two of the four M&M's are yellow. P(x > 2) =.10282 x If you repeatedly select random samples of four peanut M&M's, on average how many do you expect to be yellow? .6 x yellow M&M's With what standard deviation? .7266 x yellow M&M's 12 s米 14 f6 17 fe 20 fg %23 & 3. 4. 6. 7. 80 (O LO %24
According to a recent study, 20% of peanut M&M's are brown, 12% are yellow, 13% are red, 22% are blue. 18% are orange, and 15% are green. Assume these proportions are correct and suppose you randomly select four peanut M&M's from an extra-large bag of the candies. Calculate the following probablities. Also calculate the mean and standard deviation of the distribution. Round all solutions to four decimal places. necessary. Compute the probability that exactly two of the four M&M's are yellow. P(r = 2) .0669 Compute the probability that two or three of the four M&M's are yellow. P(x = 2 or c = 3) = .0730 Compute the probability that at most two of the four M&M's are yellow. P(x < 2) = .9937 Compute the probability that at least two of the four M&M's are yellow. P(x > 2) =| .10282 x If you repeatedly select random samples of four peanut M&M's, on average how many do you expect to be yellow? .6° x yellow M&M's With what standard deviation? f2 f3 f4 fs 米 f6 17 fe 20 @ & 2. 3. 4 LO %24 %23
Transcribed Image Text:According to a recent study, 20% of peanut M&M's are brown, 12% are yellow, 13% are red, 22% are blue. 18% are orange, and 15% are green. Assume these proportions are correct and suppose you randomly select four peanut M&M's from an extra-large bag of the candies. Calculate the following probablities. Also calculate the mean and standard deviation of the distribution. Round all solutions to four decimal places. necessary. Compute the probability that exactly two of the four M&M's are yellow. P(r = 2) .0669 Compute the probability that two or three of the four M&M's are yellow. P(x = 2 or c = 3) = .0730 Compute the probability that at most two of the four M&M's are yellow. P(x < 2) = .9937 Compute the probability that at least two of the four M&M's are yellow. P(x > 2) =| .10282 x If you repeatedly select random samples of four peanut M&M's, on average how many do you expect to be yellow? .6° x yellow M&M's With what standard deviation? f2 f3 f4 fs 米 f6 17 fe 20 @ & 2. 3. 4 LO %24 %23
Expert Solution
Step 1

Solution

X:No of yellow M&m;s

n=4

p=0.12

q=1-0.12=0.88

P(x=X)=Cxnpxqn-x

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