Four acrobats of mass 75.0 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower,with each acrobat standing on the shoulders of another acrobat. The 75.0 kg acrobatis at the bottom of the tower.What is the normal force acting on the 75.0 kg acrobat?If the area of each of the 75.0-kg acrobat's shoes is 425 cm, what average pressure(not including the atmospheric pressure) does the column of acrobats exert on thefloor?PaWill the pressure be the same if a different acrobat is on the bottom (Yes or No)?

Given, Four acrobats of mass, m1= 75 kgm2= 68 kgm3= 62 kgm4= 55 kgArea of 75 kg acrobat's shoe = 425…

Answered: Four acrobats of mass 75.0 kg, 68.0 kg,…

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