Formic acid, HCOOH, occurs naturally in the venom of bee and ant stings. It was originally isolated by the distillation of ant bodies. What are the changes in free energy, enthalpy and entropy and the sign of work for the following process carried out at 120.0° C. The boiling point of HCOOH is 100.8° C. HCOOH (I) – HCOOH (9) 45° ✔w AHO AG Compare the experimental temperature, 120.0°C, to the boiling point. AG is an indication of whether or not this reaction will proceed at this temperature. At the transition temperature, the system is at equilibrium. Does this process require the input of heat (endothermic) or is heat given off (exothermic)? Which is higher, the entropy of liquids or gases? There is a large difference in the volume of liquids and gases. Since w = -PextAV, what is the sign of work?
Formic acid, HCOOH, occurs naturally in the venom of bee and ant stings. It was originally isolated by the distillation of ant bodies. What are the changes in free energy, enthalpy and entropy and the sign of work for the following process carried out at 120.0° C. The boiling point of HCOOH is 100.8° C. HCOOH (I) – HCOOH (9) 45° ✔w AHO AG Compare the experimental temperature, 120.0°C, to the boiling point. AG is an indication of whether or not this reaction will proceed at this temperature. At the transition temperature, the system is at equilibrium. Does this process require the input of heat (endothermic) or is heat given off (exothermic)? Which is higher, the entropy of liquids or gases? There is a large difference in the volume of liquids and gases. Since w = -PextAV, what is the sign of work?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Transcribed Image Text:Formic acid, HCOOH, occurs naturally in the venom of bee and ant stings. It was originally isolated by the distillation of ant bodies.
What are the changes in free energy, enthalpy and entropy and the sign of work for the following process carried out at 120.0° C. The boiling point of HCOOH is 100.8° C.
HCOOH (1)→ HCOOH (g)
AS°
W
AHO
✓ AGº
Compare the experimental temperature, 120.0°C, to the boiling point. AGO is an indication of whether or not this reaction will proceed at this temperature. At the transition temperature, the system is at equilibrium. Does this process require the input of heat (endothermic) or is
heat given off (exothermic)? Which is higher, the entropy of liquids or gases? There is a large difference in the volume of liquids and gases. Since w = -PextAV, what is the sign of work?
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