format each dictionary item as a text string in the input file. convert each input string into a dictionary item format each item of your inverted dictionary as a text string in the output file.
format each dictionary item as a text string in the input file. convert each input string into a dictionary item format each item of your inverted dictionary as a text string in the output file.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Please help me with my Output as I had tried to add more colors in my dictionary and won't accept my append, update nor join methods as my assignment instructions as follows:
format each dictionary item as a text string in the input file.
convert each input string into a dictionary item
format each item of your inverted dictionary as a text string in the output file.
( I think I've done all of the above but my challenge was as follows:)
Create an input file with your original three or more items and add at least three new items, for a total of at least six items.
![File Edit Format Run Options Window Help
#Unit 8 Learning Journal Assignment
def invert_dict (color) :
invert=dict ()
for key, value in color.items () :
invert[value] - invert.get (value, [])+[key]
#print (invert)
return invert
#defining color dictionary
color = {'white':'orange', 'pink': 'blue'}
for key, value in color.items ():
update [value] = update.get (value, []+[key]
'brown', 'green')
print ("Update:", invert_dict (color))
print ("Original:",color)
print ("Inverted: ",invert_dict (color))
#print (invert)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b3e0ad1-27e4-45d5-9d4c-cf1a19e4c930%2F6cb6b3e1-432d-4eee-a220-376ff8b15700%2Flkt3bx6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:File Edit Format Run Options Window Help
#Unit 8 Learning Journal Assignment
def invert_dict (color) :
invert=dict ()
for key, value in color.items () :
invert[value] - invert.get (value, [])+[key]
#print (invert)
return invert
#defining color dictionary
color = {'white':'orange', 'pink': 'blue'}
for key, value in color.items ():
update [value] = update.get (value, []+[key]
'brown', 'green')
print ("Update:", invert_dict (color))
print ("Original:",color)
print ("Inverted: ",invert_dict (color))
#print (invert)
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