Formal Languages and Automata Lesson Recalling roman numerals, I=1, V=5, X=1O, L=50, C=100, D=500, M=1000, and ( For example: 489 (400+80+9) is shown by CDLXXXIX ) 947 (900+40+7) is shown by CMXLVII ) 52 ( 50+2) is shown by LII ) a.) considering the alphabet {I, V, X, L, C}, give a DFA (state transition diagram only !) that accepts roman numbers from 1 to 99.

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Formal Languages and Automata Lesson
Recalling roman numerals, l=1, V=5, X=10, L=50,
C=100, D=500, M=1000, and
( For example: 489 (400+80+9) is shown by
CDLXXXIX ) 947 (900+40+7) is shown by
CMXLVII ) 52 ( 50+2) is shown by LII)
a.) considering the alphabet {I, V, X, L, C}, give a
DFA (state transition diagram only !) that accepts
roman numbers from 1 to 99.
b.) considering the alphabet {I, V, X, L, C, D, M},
give an e-NFA (state transition diagram only !)
that accepts roman numbers from 1 to 999.
Transcribed Image Text:Formal Languages and Automata Lesson Recalling roman numerals, l=1, V=5, X=10, L=50, C=100, D=500, M=1000, and ( For example: 489 (400+80+9) is shown by CDLXXXIX ) 947 (900+40+7) is shown by CMXLVII ) 52 ( 50+2) is shown by LII) a.) considering the alphabet {I, V, X, L, C}, give a DFA (state transition diagram only !) that accepts roman numbers from 1 to 99. b.) considering the alphabet {I, V, X, L, C, D, M}, give an e-NFA (state transition diagram only !) that accepts roman numbers from 1 to 999.
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