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form TL My .ly - ly , +,- ce20 + ttin20. a , tan20- sin20 + Tycor20, Imaksmin - + )' + rà, 2 Tmak A 3 m long steel angle shown in the figure has a section thickness of 12.7 mm and a cross sectional area of 4350 mm ^ 2. Find the resulting torsion angle in degrees. T= 500 Nm ve G = 77,2 GPa () 5.34 3.89 4,87 7,86 8,72

form TL My .ly - ly , +,- ce20 + ttin20. a , tan20- sin20 + Tycor20, Imaksmin - + )' + rà, 2 Tmak A 3 m long steel angle shown in the figure has a section thickness of 12.7 mm and a cross sectional area of 4350 mm ^ 2. Find the resulting torsion angle in degrees. T= 500 Nm ve G = 77,2 GPa () 5.34 3.89 4,87 7,86 8,72

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Formül; TL 2 5 için c - cz -;(1– 0,630b/a) M-(lzy.2– ly.y) + M,(1;.z – Izy -y) 1.ly – Izy Ox + dy, tan28p = Tmaks = Gab? Czab'G" m VQ TD It Мy 2tA Ox + Oy x-dy cos20 + Trysin20 , Jort = Ox + 0y Ty'y' = - sin20 + Trycos20 , Omaks.min = +r (Ox – + Ty Tmaks = A 3 m long steel angle shown in the figure has a section thickness of 12.7 mm and a cross sectional area of 4350 mm ^ 2. Find the resulting torsion angle in degrees. T = 500 Nm ve G = 77,2 GPa (°) O 5,34 O 3,89 O 4,87 O 7,86 O 8.72 O O O O
Transcribed Image Text:Formül; TL 2 5 için c - cz -;(1– 0,630b/a) M-(lzy.2– ly.y) + M,(1;.z – Izy -y) 1.ly – Izy Ox + dy, tan28p = Tmaks = Gab? Czab'G" m VQ TD It Мy 2tA Ox + Oy x-dy cos20 + Trysin20 , Jort = Ox + 0y Ty'y' = - sin20 + Trycos20 , Omaks.min = +r (Ox – + Ty Tmaks = A 3 m long steel angle shown in the figure has a section thickness of 12.7 mm and a cross sectional area of 4350 mm ^ 2. Find the resulting torsion angle in degrees. T = 500 Nm ve G = 77,2 GPa (°) O 5,34 O 3,89 O 4,87 O 7,86 O 8.72 O O O O
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