Forces of magnitude F; =7 kN in the +y direction and F 2 =13 kN in Question 2) the -z direction are acting on the arm from point B in the figure . From the point C, a moment of magnitude M=5 kN.m acts in the +y direction . The lengths of the arm are also given as L =0.2 m and L2=0.3 m . The radius r in the aa section taken over the arm is r=0.013 m and it is desired to determine the stress state at point A. The shear modulus of the sleeve material is G=75 Gpa . According to this; S2 Question 2-A) in MPa .) Find the shear stress due to the shear force at point A. ( Write your result

Forces of magnitude F; =7 kN in the +y direction and F 2 =13 kN in Question 2) the -z direction are acting on the arm from point B in the figure . From the point C, a moment of magnitude M=5 kN.m acts in the +y direction . The lengths of the arm are also given as L =0.2 m and L2=0.3 m . The radius r in the aa section taken over the arm is r=0.013 m and it is desired to determine the stress state at point A. The shear modulus of the sleeve material is G=75 Gpa . According to this; S2 Question 2-A) in MPa .) Find the shear stress due to the shear force at point A. ( Write your result

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Forces of F1=15 kN in the z direction from the B point, F2=10 kN in the z direction from the C point and F3=10 kN in the y direction act on the arm in the figure. The lengths of the arm are also given as L1=0.15 m and L2=0.16 m. The radius r in the a-a section taken over the arm is r=0.2 m and it is desired to determine the stress state at point A. The shear modulus of the sleeve material is G=65 Gpa. According to this; WRITE YOUR RESULTS IN THE BOXES WITHOUT THE UNITS IN kPa. a) Find the shear stress due to the shear force at point A. Response b) Find the shear stress due to the torsional moment at point A. Response c) Find the total shear stress at point A. Response d) Find the normal stress due to the normal force at point A. Response e) Find the normal stress due to the bending moment at point A. Response f) Find the total normal stress at point A. Response
t = A rigid system DA is subjected to two forces at point A as shown in the figure below. Given FAB= -0.47i +0.47j - 1.884k (KN) and FAC -2.34i +1.872k (KN). D 4m Z A FAB 4m. 4m FAC B(4,5,0) a) The magnitude of moment caused by force FAB about y-axis is b) The magnitude of moment caused by force FAC about OB is c) The resultant moment due to FAB and FAC about origin O is KN.m and its direction is KN.m and its direction is KN.m
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Find the magnitude and direction of the resultant force for the system of forces shown in the figure. Where F, -30 N, F2 =5N, F3 =30 N, F4 30N, Fs = 30N & F6 - 70N. The angles e, =15, e; =35, 04 = 20°, e, = 25• (Enter only the values in the boxes by referring the units given in bracket) F2 F6 Fs (1) The horizontal component EH of the given system is (unit is in N) (2) The vertical component EV of the given system is (unit is in N) = (3) The resultant of the given force system is (unit in N) = (4) The direction of Resultant is (in") =
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Question 2) Forces of F1=7 kN in the +y direction and F2=13 kN in the -z direction are acting on the arm from point B in the figure. From the point C, a moment of magnitude M=4 kN.m acts in the +y direction. The lengths of the arm are also given as L1=0.8 m and L2=0.6 m. The radius r in the a-a section taken over the arm is r=0.023 m and it is desired to determine the stress state at point A. The shear modulus of the sleeve material is G=78 Gpa. According to this;Question 2-D) Find the normal stress that occurs at point A due to the bending moment (formed by the F1 force). (Write your result in MPa.)Question 2-E) Find the amount of torsion (angle) that occurs at point A due to the torque created by the forces. (Write your result in degrees.)
Question 2) Forces of F1=7 kN in the +y direction and F2=13 kN in the -z direction are acting on the arm from point B in the figure. From the point C, a moment of magnitude M=4 kN.m acts in the +y direction. The lengths of the arm are also given as L1=0.8 m and L2=0.6 m. The radius r in the a-a section taken over the arm is r=0.023 m and it is desired to determine the stress state at point A. The shear modulus of the sleeve material is G=78 Gpa. According to this;Question 2-A) Find the shear stress at point A due to the shear force. (Write your result in MPa.)Question 2-B) Find the shear stress due to the torsional moment at point A. (Write your result in MPa.)Question 2-C) Find the normal stress caused by the normal force at point A. (Write your result in MPa.)
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What is the magnitude of the moment done by the force about the "z-axis" in the following figure. 4 m F= (60i-50j- 20k} N 3 m 7 m 4m 6 m 2 m Window
Find the moment of the Force P in the figure relative to the axis AD in terms of unit vectors.
Forces of F1=8 kN in the z direction from the B point, F2=5 kN in the z direction from the C point, and F3=10 kN in the y direction act on the arm in the figure. The lengths of the arm are also given as L1=0.15 m and L2=0.16 m. The radius r in the a-a section taken over the arm is r=0.2 m and it is desired to determine the stress state at point A. slip of sleeve material module is G=75 Gpa. Accordingly, a) Find the shear stress due to the shear force at point A. b) Find the shear stress due to the torsional moment at point A. c) Find the total shear stress at point A. d) Find the normal stress due to the normal force at point A. e) Find the normal stress due to the bending moment at point A. f) Find the total normal stress at point A.