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force is projected from point A, at distance a from the center of force O, in a direction perpendicular to OA, its projection velocity becomes half of the velocity required for a circular orbit of radius a.   Here, how can we find the angular momentum and show that the radial equation of motion is

force is projected from point A, at distance a from the center of force O, in a direction perpendicular to OA, its projection velocity becomes half of the velocity required for a circular orbit of radius a.   Here, how can we find the angular momentum and show that the radial equation of motion is

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When the particle with a given central force is projected from point A, at distance a from the center of force O, in a direction perpendicular to OA, its projection velocity becomes half of the velocity required for a circular orbit of radius a.

 

Here, how can we find the angular momentum and show that the radial equation of motion is :

 

ji – 9 ka 4 r³ || 3k p2
Transcribed Image Text:ji – 9 ka 4 r³ || 3k p2
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