force, force to bind them into another and one A third proton approaches the deuteron and is initially repelled by the but they do get close enough together for the new nucleus. This is now called helium-3, consisting of two Finally, two helium-3 nuclei overcome their the repulsion and bind together via force, releasing two protons in the process. The final result is a stable This entire process mass than the nucleus of helium-4, consisting of two and two releases energy because the four protons we started with have resulting helium-4 nucleus, and because of the equation Select from the following word/equation bank to fill in each blank above: electric 12. Citytty

Question
#10 All four of the fundamental forces have gotten involved by this point, but the process is
not yet complete. Fill in the blanks below to make a stable nucleus of helium-4:
A third proton approaches the deuteron and is initially repelled by the
but they do get close enough together for the
new nucleus. This is now called helium-3, consisting of two
force,
force to bind them into another
and one
Finally, two helium-3 nuclei overcome their
the
repulsion and bind together via
force, releasing two protons in the process. The final result is a stable
nucleus of helium-4, consisting of two
and two
This entire process
releases energy because the four protons we started with have
mass than the
resulting helium-4 nucleus, and because of the equation
Select from the following word/equation
bank to fill in each blank above:
• electric
• gravitational
• less
• more
•
neutron(s)
• proton(s)
| Foras =
=
Giftytty
p
F₂ = qvB sin a
E = (Am)e²
10:33 PM
Transcribed Image Text:#10 All four of the fundamental forces have gotten involved by this point, but the process is not yet complete. Fill in the blanks below to make a stable nucleus of helium-4: A third proton approaches the deuteron and is initially repelled by the but they do get close enough together for the new nucleus. This is now called helium-3, consisting of two force, force to bind them into another and one Finally, two helium-3 nuclei overcome their the repulsion and bind together via force, releasing two protons in the process. The final result is a stable nucleus of helium-4, consisting of two and two This entire process releases energy because the four protons we started with have mass than the resulting helium-4 nucleus, and because of the equation Select from the following word/equation bank to fill in each blank above: • electric • gravitational • less • more • neutron(s) • proton(s) | Foras = = Giftytty p F₂ = qvB sin a E = (Am)e² 10:33 PM
but they do get close enough together for the
new nucleus. This is now called helium-3, consisting of two
Finally, two helium-3 nuclei overcome their
the
repelled by the
force,
force to bind them into another
and one
repulsion and bind together via
force, releasing two protons in the process. The final result is a stable
nucleus of helium-4, consisting of two
and two
releases energy because the four protons we started with have
resulting helium-4 nucleus, and because of the equation
Select from the following word/equation
bank to fill in each blank above:
|Foras Gtttt
• electric
• gravitational
• less
• more
• neutron(s)
• proton(s)
• strong
• weak
This entire process
mass than the
||=1921
p
F = que sin d
E = (Am)e²
Kmax
λ===
Epheton-Eg
*
PEM
10:39 PM
Transcribed Image Text:but they do get close enough together for the new nucleus. This is now called helium-3, consisting of two Finally, two helium-3 nuclei overcome their the repelled by the force, force to bind them into another and one repulsion and bind together via force, releasing two protons in the process. The final result is a stable nucleus of helium-4, consisting of two and two releases energy because the four protons we started with have resulting helium-4 nucleus, and because of the equation Select from the following word/equation bank to fill in each blank above: |Foras Gtttt • electric • gravitational • less • more • neutron(s) • proton(s) • strong • weak This entire process mass than the ||=1921 p F = que sin d E = (Am)e² Kmax λ=== Epheton-Eg * PEM 10:39 PM
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