#36 AP Physics 1 FORCE 1FORCE 2F (N)F (N)1.2-1.2-1.0-1.00.8-0.8-0.60.4-0.2-0.0+0.0 0.2 0.40.60.4+0.2-0.0+0.0 0.2 0.4x (m)►x (m)1.00.6 0.81.00.6 0.836. The graphs above show the magnitude F of a force exerted on an object as a function of the object's position xfor two trials in an experiment. W and W, are the work done on the object by force 1 and force 2, respectively.How do W, and W, compare, and why?(A) W, > W, , because the maximum value of force 1 is greater than the maximum value of force 2.(B) W, > W, , because the slope of force 1's graph increases, while the slope of force 2's graph decreases.(C) W, < W, , because the average value of force 1 is smaller than the average value of force 2.(D) W, < W, , because at the midpoint, x = 0.5 m , the value of force 1 is less than the value of force 2.

Name: #36 AP Physics 1 FORCE 1FORCE 2F (N)F (N)1.2-1.2-1.0-1.00.8-0.8-0.60.4
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Description: #36 AP Physics 1 FORCE 1FORCE 2F (N)F (N)1.2-1.2-1.0-1.00.8-0.8-0.60.4-0.2-0.0+0.0 0.2 0.40.60.4+0.2-0.0+0.0 0.2 0.4x (m)►x (m)1.00.6 0.81.00.6 0.836. The graphs above show the magnitude F of a force exerted on an object as a function of the object's

Work done is defined as the product of force and the displacement along that force. In a force and…

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Physics

FORCE 1 FORCE 2 F (N) F (N) 1.2 1.2- 1.0 1.0- 0.8 0.8- 0.6 0.4 0.2- 0.0- 0.0 0.6- 0.4- 0.2- ( (m) 1.0 0.0- 0.0 0.2 x (m) 1.0 0.2 0.4 0.6 0.8 0.4 0.6 0.8 36. The graphs above show the magnitude F of a force exerted on an object as a function of the object's position x for two trials in an experiment. W and W are the work done on the object by force 1 and force 2, respectively. How do W, and W2 compare, and why? (A) W, > W, , because the maximum value of force 1 is greater than the maximum value of force 2. (B) W, > W, , because the slope of force 1's graph increases, while the slope of force 2's graph decreases. (C) W, < W, , because the average value of force 1 is smaller than the average value of force 2. (D) W, < W, , because at the midpoint, x = 0.5 m , the value of force 1 is less than the value of force 2.

FORCE 1 FORCE 2 F (N) F (N) 1.2 1.2- 1.0 1.0- 0.8 0.8- 0.6 0.4 0.2- 0.0- 0.0 0.6- 0.4- 0.2- ( (m) 1.0 0.0- 0.0 0.2 x (m) 1.0 0.2 0.4 0.6 0.8 0.4 0.6 0.8 36. The graphs above show the magnitude F of a force exerted on an object as a function of the object's position x for two trials in an experiment. W and W are the work done on the object by force 1 and force 2, respectively. How do W, and W2 compare, and why? (A) W, > W, , because the maximum value of force 1 is greater than the maximum value of force 2. (B) W, > W, , because the slope of force 1's graph increases, while the slope of force 2's graph decreases. (C) W, < W, , because the average value of force 1 is smaller than the average value of force 2. (D) W, < W, , because at the midpoint, x = 0.5 m , the value of force 1 is less than the value of force 2.

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

#36 AP Physics 1

FORCE 1
FORCE 2
F (N)
F (N)
1.2-
1.2-
1.0-
1.0
0.8-
0.8-
0.6
0.4-
0.2-
0.0+
0.0 0.2 0.4
0.6
0.4+
0.2-
0.0+
0.0 0.2 0.4
x (m)
►x (m)
1.0
0.6 0.8
1.0
0.6 0.8
36. The graphs above show the magnitude F of a force exerted on an object as a function of the object's position x
for two trials in an experiment. W and W, are the work done on the object by force 1 and force 2, respectively.
How do W, and W, compare, and why?
(A) W, > W, , because the maximum value of force 1 is greater than the maximum value of force 2.
(B) W, > W, , because the slope of force 1's graph increases, while the slope of force 2's graph decreases.
(C) W, < W, , because the average value of force 1 is smaller than the average value of force 2.
(D) W, < W, , because at the midpoint, x = 0.5 m , the value of force 1 is less than the value of force 2.

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