5412. AT= 53.56 106. Assuming that a human body climbs with an energy efficiency of 20%, how high a hill does a 167 lb hiker need to climb to completely burn off a 1000 (food) calorie meal? (hint: This involves the change in potential energy of the hiker, APE = mgAh, note that 1 kilograms weighs about 2.2 lbs, and that 1 dietary calorie contains 4186 Joules.) a. 3.15 x 10³ m b. 1.91 x 10³ m c. 1.13 x 10³ m d. 2.48 x 10³ m
5412. AT= 53.56 106. Assuming that a human body climbs with an energy efficiency of 20%, how high a hill does a 167 lb hiker need to climb to completely burn off a 1000 (food) calorie meal? (hint: This involves the change in potential energy of the hiker, APE = mgAh, note that 1 kilograms weighs about 2.2 lbs, and that 1 dietary calorie contains 4186 Joules.) a. 3.15 x 10³ m b. 1.91 x 10³ m c. 1.13 x 10³ m d. 2.48 x 10³ m
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please help with #106 :)
![May 10, 2023, 4:32 PM
a. Nothing: The waste heat
b. Entropy
c. Combustion products
d. Thermal energy generated only by friction
105. Suppose a suspended mass of 519 kg moves downwards through a distance of 57 m as it turns a paddle
wheel in 1.293 kilograms of water initially at a temperature of 2°C: How much will the temperature of the
water increase if all the energy released by the falling mass is transfered to and remains in the water?
(hint: Recall that Q = mcAT, and consider the change in potential energy of the falling mass, APE = mgAh,
as the source of energy here, and that the heat capacity of water is 4186 Joules/(kg.° C)
b.
96.4 °C
a. 53.6 °C E = mgh = (519 kg) (9.8 m/s²) (57 m) = 289913.4J
Q = E=2899 13.4 J = (1.293 kg) (4186J/kg°c) AT
c. 145 °C
d. 118 °C
5412.498
5412.498
AT = 53.56
106. Assuming that a human body climbs with an energy efficiency of 20%, how high a hill does a 167 lb
hiker need to climb to completely burn off a 1000 (food) calorie meal? (hint: This involves the change in
potential energy of the hiker, APE = mgAh, note that 1 kilograms weighs about 2.2 lbs, and that 1 dietary
calorie contains 4186 Joules.)
0.48
a. 3.15 x 10³ m
migh
1 19
b. 1.91 x 10³ m
c. 1.13 x 10³ m
d. 2.48 x 10³ m
02
c. 3.52 x 10³ J
d. 7.39 x 10³ J
*$X(4-1863
107. How much heat must be added to 6 moles of an monatomic ideal gas kept at a constant VOLUME to increase
its temperature by 47 °C?yancy effec
a. 1.06 x 10³ J
b. 4.92 x 10³ J
4,186,0
sash outovi
108. How much heat must be added to 3 moles of an monatomic ideal gas kept at a constant PRESSURE to
increase its temperature by 44 °C?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb3bf8d9f-79bd-47af-b660-4bc5b007f58d%2F80504dab-d776-42f1-a17d-720f1663c4c6%2Fvpicse_processed.jpeg&w=3840&q=75)
Transcribed Image Text:May 10, 2023, 4:32 PM
a. Nothing: The waste heat
b. Entropy
c. Combustion products
d. Thermal energy generated only by friction
105. Suppose a suspended mass of 519 kg moves downwards through a distance of 57 m as it turns a paddle
wheel in 1.293 kilograms of water initially at a temperature of 2°C: How much will the temperature of the
water increase if all the energy released by the falling mass is transfered to and remains in the water?
(hint: Recall that Q = mcAT, and consider the change in potential energy of the falling mass, APE = mgAh,
as the source of energy here, and that the heat capacity of water is 4186 Joules/(kg.° C)
b.
96.4 °C
a. 53.6 °C E = mgh = (519 kg) (9.8 m/s²) (57 m) = 289913.4J
Q = E=2899 13.4 J = (1.293 kg) (4186J/kg°c) AT
c. 145 °C
d. 118 °C
5412.498
5412.498
AT = 53.56
106. Assuming that a human body climbs with an energy efficiency of 20%, how high a hill does a 167 lb
hiker need to climb to completely burn off a 1000 (food) calorie meal? (hint: This involves the change in
potential energy of the hiker, APE = mgAh, note that 1 kilograms weighs about 2.2 lbs, and that 1 dietary
calorie contains 4186 Joules.)
0.48
a. 3.15 x 10³ m
migh
1 19
b. 1.91 x 10³ m
c. 1.13 x 10³ m
d. 2.48 x 10³ m
02
c. 3.52 x 10³ J
d. 7.39 x 10³ J
*$X(4-1863
107. How much heat must be added to 6 moles of an monatomic ideal gas kept at a constant VOLUME to increase
its temperature by 47 °C?yancy effec
a. 1.06 x 10³ J
b. 4.92 x 10³ J
4,186,0
sash outovi
108. How much heat must be added to 3 moles of an monatomic ideal gas kept at a constant PRESSURE to
increase its temperature by 44 °C?
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