For which of the following reactions is Kp = Kc? I. CO(g) + H20(1) = CO2(g) + H2(g) II. H2(g) + Br2(1) = 2HBr(g) III. 2NO(g) + O2(g) = IV. N2(g) + 2H2(g) = N2H4(g) V. Ch(9) + F2(9) = 2CIF(g) 2NO2(g) IV only I only O Ill only O Il only O vonly

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The image presents a question about chemical equilibrium, specifically asking for which reactions the equilibrium constants \( K_p \) and \( K_c \) are equal.

**Question:**

For which of the following reactions is \( K_p = K_c \)?

I. \( \text{CO(g)} + \text{H}_2\text{O(l)} \rightleftharpoons \text{CO}_2\text{(g)} + \text{H}_2\text{(g)} \)

II. \( \text{H}_2\text{(g)} + \text{Br}_2\text{(l)} \rightleftharpoons 2\text{HBr(g)} \)

III. \( 2\text{NO(g)} + \text{O}_2\text{(g)} \rightleftharpoons 2\text{NO}_2\text{(g)} \)

IV. \( \text{N}_2\text{(g)} + 2\text{H}_2\text{(g)} \rightleftharpoons \text{N}_2\text{H}_4\text{(g)} \)

V. \( \text{Cl}_2\text{(g)} + \text{F}_2\text{(g)} \rightleftharpoons 2\text{ClF(g)} \)

**Options:**

- IV only
- I only
- III only
- II only
- V only

**Explanation:**

For \( K_p \) to be equal to \( K_c \), the change in the number of moles of gas (\( \Delta n \)) in the reaction must be zero. The reactions with no change in the number of gas molecules on either side will have \( K_p = K_c \).

**Solution:**
- Reaction I: \( \Delta n = 1 \) (1 gas product, 0 gas reactants)
- Reaction II: \( \Delta n = 1 \) (1 gas product, 0 gas reactants)
- Reaction III: \( \Delta n = 0 \) (2 gas products, 2 gas reactants)
- Reaction IV: \( \Delta n = -1 \) (1 gas product, 2 gas reactants)
- Reaction V: \( \Delta n = 0 \
Transcribed Image Text:The image presents a question about chemical equilibrium, specifically asking for which reactions the equilibrium constants \( K_p \) and \( K_c \) are equal. **Question:** For which of the following reactions is \( K_p = K_c \)? I. \( \text{CO(g)} + \text{H}_2\text{O(l)} \rightleftharpoons \text{CO}_2\text{(g)} + \text{H}_2\text{(g)} \) II. \( \text{H}_2\text{(g)} + \text{Br}_2\text{(l)} \rightleftharpoons 2\text{HBr(g)} \) III. \( 2\text{NO(g)} + \text{O}_2\text{(g)} \rightleftharpoons 2\text{NO}_2\text{(g)} \) IV. \( \text{N}_2\text{(g)} + 2\text{H}_2\text{(g)} \rightleftharpoons \text{N}_2\text{H}_4\text{(g)} \) V. \( \text{Cl}_2\text{(g)} + \text{F}_2\text{(g)} \rightleftharpoons 2\text{ClF(g)} \) **Options:** - IV only - I only - III only - II only - V only **Explanation:** For \( K_p \) to be equal to \( K_c \), the change in the number of moles of gas (\( \Delta n \)) in the reaction must be zero. The reactions with no change in the number of gas molecules on either side will have \( K_p = K_c \). **Solution:** - Reaction I: \( \Delta n = 1 \) (1 gas product, 0 gas reactants) - Reaction II: \( \Delta n = 1 \) (1 gas product, 0 gas reactants) - Reaction III: \( \Delta n = 0 \) (2 gas products, 2 gas reactants) - Reaction IV: \( \Delta n = -1 \) (1 gas product, 2 gas reactants) - Reaction V: \( \Delta n = 0 \
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