For what values of h is the vector 4 Span 1 2 ·|- in 3 h² +5 0 1 1 0 2 2 H h = -1 H h can be any real numbers. h = 1 h = -1 and h=1 D No such values for h. ?
For what values of h is the vector 4 Span 1 2 ·|- in 3 h² +5 0 1 1 0 2 2 H h = -1 H h can be any real numbers. h = 1 h = -1 and h=1 D No such values for h. ?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![### Linear Algebra Problem: Vector in Span
**Problem:**
For what values of \( h \) is the vector
\[
\begin{bmatrix}
1 \\
2 \\
3 \\
h^2 + 5
\end{bmatrix}
\]
in
\[
\text{Span} \left\{
\begin{bmatrix}
1 \\
0 \\
0 \\
2
\end{bmatrix},
\begin{bmatrix}
0 \\
1 \\
0 \\
2
\end{bmatrix},
\begin{bmatrix}
1 \\
1 \\
1 \\
2
\end{bmatrix}
\right\}?
\]
**Explanation:**
To determine for which values of \( h \) the vector lies in the span of the given set, we need to understand when the vector can be written as a linear combination of the given vectors.
**Options for \( h \):**
1. \( h \) can be any real number.
2. \( h = -1 \)
3. \( h = -1 \) and \( h = 1 \) *(Correct Answer)*
4. \( h = 1 \)
5. No such values for \( h \).
The correct solution, \( h = -1 \) and \( h = 1 \), is highlighted in blue, indicating that these are the values of \( h \) that allow the vector to lie in the span of the given set of vectors.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F39c511f9-cd3c-4c9c-bb28-dea2f3d58d78%2F261f465a-a8cc-40e6-880f-cf4d7ac26e76%2Fbm1tbvk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Linear Algebra Problem: Vector in Span
**Problem:**
For what values of \( h \) is the vector
\[
\begin{bmatrix}
1 \\
2 \\
3 \\
h^2 + 5
\end{bmatrix}
\]
in
\[
\text{Span} \left\{
\begin{bmatrix}
1 \\
0 \\
0 \\
2
\end{bmatrix},
\begin{bmatrix}
0 \\
1 \\
0 \\
2
\end{bmatrix},
\begin{bmatrix}
1 \\
1 \\
1 \\
2
\end{bmatrix}
\right\}?
\]
**Explanation:**
To determine for which values of \( h \) the vector lies in the span of the given set, we need to understand when the vector can be written as a linear combination of the given vectors.
**Options for \( h \):**
1. \( h \) can be any real number.
2. \( h = -1 \)
3. \( h = -1 \) and \( h = 1 \) *(Correct Answer)*
4. \( h = 1 \)
5. No such values for \( h \).
The correct solution, \( h = -1 \) and \( h = 1 \), is highlighted in blue, indicating that these are the values of \( h \) that allow the vector to lie in the span of the given set of vectors.
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