For what values of h is the vector 4 Span 1 2 ·|- in 3 h² +5 0 1 1 0 2 2 H h = -1 H h can be any real numbers. h = 1 h = -1 and h=1 D No such values for h. ?

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Solve this linear algebra multiple choice question.. 

### Linear Algebra Problem: Vector in Span

**Problem:**

For what values of \( h \) is the vector 

\[ 
\begin{bmatrix}
1 \\
2 \\
3 \\
h^2 + 5 
\end{bmatrix} 
\] 

in 

\[ 
\text{Span} \left\{ 
\begin{bmatrix}
1 \\ 
0 \\ 
0 \\ 
2 
\end{bmatrix}, 
\begin{bmatrix}
0 \\ 
1 \\ 
0 \\ 
2 
\end{bmatrix}, 
\begin{bmatrix}
1 \\ 
1 \\ 
1 \\ 
2 
\end{bmatrix} 
\right\}?
\]

**Explanation:**

To determine for which values of \( h \) the vector lies in the span of the given set, we need to understand when the vector can be written as a linear combination of the given vectors.

**Options for \( h \):**

1. \( h \) can be any real number.
2. \( h = -1 \)
3. \( h = -1 \) and \( h = 1 \)  *(Correct Answer)*
4. \( h = 1 \)
5. No such values for \( h \).

The correct solution, \( h = -1 \) and \( h = 1 \), is highlighted in blue, indicating that these are the values of \( h \) that allow the vector to lie in the span of the given set of vectors.
Transcribed Image Text:### Linear Algebra Problem: Vector in Span **Problem:** For what values of \( h \) is the vector \[ \begin{bmatrix} 1 \\ 2 \\ 3 \\ h^2 + 5 \end{bmatrix} \] in \[ \text{Span} \left\{ \begin{bmatrix} 1 \\ 0 \\ 0 \\ 2 \end{bmatrix}, \begin{bmatrix} 0 \\ 1 \\ 0 \\ 2 \end{bmatrix}, \begin{bmatrix} 1 \\ 1 \\ 1 \\ 2 \end{bmatrix} \right\}? \] **Explanation:** To determine for which values of \( h \) the vector lies in the span of the given set, we need to understand when the vector can be written as a linear combination of the given vectors. **Options for \( h \):** 1. \( h \) can be any real number. 2. \( h = -1 \) 3. \( h = -1 \) and \( h = 1 \) *(Correct Answer)* 4. \( h = 1 \) 5. No such values for \( h \). The correct solution, \( h = -1 \) and \( h = 1 \), is highlighted in blue, indicating that these are the values of \( h \) that allow the vector to lie in the span of the given set of vectors.
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