10:14 AA A bartleby.com = bartleby Q&A Math / Algebra / Q&A Library / 7:54A bartleby.com= bartleby... 7:54A bartleby.com= bartlebyQ&Aath / Al... Try Need 1:1 help? Our live tutors are available 24/7 bartleby > tutor To mulitiply matrix we have to check no. of column in first matrix should be equal to no. of rows in second matrix. first column of se cond matrix wvill multiply to each row of first matrix Hence 1xx, +0xx, -1xX3 0. Охх, +1xx, + 2хх, Охх, +0хх, — 2хх, +0-x Го] 0+x, +2x3 |0 [0+0-2x, eqquating the elements of both matrix X +0-x, =0 0+x, +2x; =0 0+0-2x, =0 from(i) (1) (ii) (iii) -2x, = 0 x, =0 Plugging in(i) X +0-0=0 plugging in (ii) 0+x, +2(0) =0 Was this solution helnful?.

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Why does -2x3=0? Does this mean I can take any number and make it equal to zero?

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To mulitiply matrix we have to check no. of column in first matrix should be equal
to no. of rows in second matrix.
first column of se cond matrix wvill multiply to each row of first matrix
Hence
1xx, +0xx, -1xX3
0.
Охх, +1xx, + 2хх,
Охх, +0хх, — 2хх,
+0-x
Го]
0+x, +2x3
|0
[0+0-2x,
eqquating the elements of both matrix
X +0-x, =0
0+x, +2x; =0
0+0-2x, =0
from(i)
(1)
(ii)
(iii)
-2x, = 0
x, =0
Plugging in(i)
X +0-0=0
plugging in (ii)
0+x, +2(0) =0
Was this solution helnful?.
Transcribed Image Text:10:14 AA A bartleby.com = bartleby Q&A Math / Algebra / Q&A Library / 7:54A bartleby.com= bartleby... 7:54A bartleby.com= bartlebyQ&Aath / Al... Try Need 1:1 help? Our live tutors are available 24/7 bartleby > tutor To mulitiply matrix we have to check no. of column in first matrix should be equal to no. of rows in second matrix. first column of se cond matrix wvill multiply to each row of first matrix Hence 1xx, +0xx, -1xX3 0. Охх, +1xx, + 2хх, Охх, +0хх, — 2хх, +0-x Го] 0+x, +2x3 |0 [0+0-2x, eqquating the elements of both matrix X +0-x, =0 0+x, +2x; =0 0+0-2x, =0 from(i) (1) (ii) (iii) -2x, = 0 x, =0 Plugging in(i) X +0-0=0 plugging in (ii) 0+x, +2(0) =0 Was this solution helnful?.
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