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For two resistors shown in the figure below, rank the currents at points a through f from largest to smallest. 30 W M A e C a 60 W W B AV d b O 1₂ = Ib> Ie= If > Ic = Id O 1a = Ib> Ic = Id > le = If Ole = If > Ic = Id > la = Ib

For two resistors shown in the figure below, rank the currents at points a through f from largest to smallest. 30 W M A e C a 60 W W B AV d b O 1₂ = Ib> Ie= If > Ic = Id O 1a = Ib> Ic = Id > le = If Ole = If > Ic = Id > la = Ib

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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**Educational Content: Understanding Circuit Currents** **Problem Statement:** For two resistors shown in the figure below, rank the currents at points \(a\) through \(f\) from largest to smallest. **Circuit Diagram:** - **Resistors:** - Resistor \( A \) is labeled with 30 W. - Resistor \( B \) is labeled with 60 W. - **Connections and Paths:** - The circuit consists of two parallel paths. - Path 1: \( e \to A \to f \) - Path 2: \( c \to B \to d \) - Both paths start at point \( a \) and end at point \( b \), connected to a voltage source represented by \(\Delta V\). **Options to Rank the Currents:** 1. \( I_a = I_b > I_e = I_f > I_c = I_d \) 2. \( I_a = I_b > I_c = I_d > I_e = I_f \) 3. \( I_e = I_f > I_c = I_d > I_a = I_b \) **Analyzing the Circuit:** - The current splits into two paths after leaving the battery at point \( a \) and combines again at point \( b \). - The path with the lower resistance (30 W) will have a higher current compared to the path with higher resistance (60 W). - Due to junction rule, the currents at points \( a \) and \( b \) will be equal as they represent the total current entering and leaving the parallel combination. **Conclusion:** To correctly rank the currents, consider the distribution due to resistance values and apply principles of parallel circuits. Choose the most logical option based on circuit analysis.
Transcribed Image Text:**Educational Content: Understanding Circuit Currents** **Problem Statement:** For two resistors shown in the figure below, rank the currents at points \(a\) through \(f\) from largest to smallest. **Circuit Diagram:** - **Resistors:** - Resistor \( A \) is labeled with 30 W. - Resistor \( B \) is labeled with 60 W. - **Connections and Paths:** - The circuit consists of two parallel paths. - Path 1: \( e \to A \to f \) - Path 2: \( c \to B \to d \) - Both paths start at point \( a \) and end at point \( b \), connected to a voltage source represented by \(\Delta V\). **Options to Rank the Currents:** 1. \( I_a = I_b > I_e = I_f > I_c = I_d \) 2. \( I_a = I_b > I_c = I_d > I_e = I_f \) 3. \( I_e = I_f > I_c = I_d > I_a = I_b \) **Analyzing the Circuit:** - The current splits into two paths after leaving the battery at point \( a \) and combines again at point \( b \). - The path with the lower resistance (30 W) will have a higher current compared to the path with higher resistance (60 W). - Due to junction rule, the currents at points \( a \) and \( b \) will be equal as they represent the total current entering and leaving the parallel combination. **Conclusion:** To correctly rank the currents, consider the distribution due to resistance values and apply principles of parallel circuits. Choose the most logical option based on circuit analysis.
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In the parallel connection, the voltage remains the same.

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