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For time t≥ 0, a particle moves in the zy-plane with velocity vector given by v(t) = (In (t³ + 3t+1), 1-In(t + 3)). At time t = 0, the particle is at position (1, -3). What is the particle's acceleration vector at time t = 2.5? A В) (-0.191, 0.033) (0.902,-0.182) (С) (3.183,-0.705) D (5.569,-4.080)

For time t≥ 0, a particle moves in the zy-plane with velocity vector given by v(t) = (In (t³ + 3t+1), 1-In(t + 3)). At time t = 0, the particle is at position (1, -3). What is the particle's acceleration vector at time t = 2.5? A В) (-0.191, 0.033) (0.902,-0.182) (С) (3.183,-0.705) D (5.569,-4.080)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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For time t > 0, a particle moves in the zy-plane with velocity vector given by v(t) = (In(t³ + 3t+1), 1- ln(t + 3)). At time t = 0, the particle is at position (1, -3). What is the particle's acceleration vector at time t = 2.5? A 1 B D J (-0.191, 0.033) (0.902,-0.182) (3.183,-0.705) (5.569,-4.080) 2 21 W F2 3 E F3 4) $ 4 R % 5 FS T * A 6 F6 * F7 & 7 U PrtScn 8 Home F9 9 End F10 0 POUP FI P PgDn F12 C
Transcribed Image Text:For time t > 0, a particle moves in the zy-plane with velocity vector given by v(t) = (In(t³ + 3t+1), 1- ln(t + 3)). At time t = 0, the particle is at position (1, -3). What is the particle's acceleration vector at time t = 2.5? A 1 B D J (-0.191, 0.033) (0.902,-0.182) (3.183,-0.705) (5.569,-4.080) 2 21 W F2 3 E F3 4) $ 4 R % 5 FS T * A 6 F6 * F7 & 7 U PrtScn 8 Home F9 9 End F10 0 POUP FI P PgDn F12 C
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