For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.In a marketing survey, a random sample of 1016 supermarket shoppers revealed that 270 always stock up on an item when they find that item at a real bargain price. (a)  Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Enter a number. Round your answer to four decimal places.) (b)  Find a 95% confidence interval for p. (For each answer, enter a number. Round your answers to three decimal places.)lower limit     upper limit     Give a brief explanation of the meaning of the interval. 95% of all confidence intervals would include the true proportion of shoppers who stock up on bargains.5% of all confidence intervals would include the true proportion of shoppers who stock up on bargains.    95% of the confidence intervals created using this method would include the true proportion of shoppers who stock up on bargains.5% of the confidence intervals created using this method would include the true proportion of shoppers who stock up on bargains. (c)  As a news writer, how would you report the survey results on the percentage of supermarket shoppers who stock up on items when they find the item is a real bargain? Report p̂ along with the margin of error.Report p̂.    Report the margin of error.Report the confidence interval. What is the margin of error based on a 95% confidence interval? (Enter a number. Round your answer to three decimal places.)

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For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.

In a marketing survey, a random sample of 1016 supermarket shoppers revealed that 270 always stock up on an item when they find that item at a real bargain price.

(a)

 Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Enter a number. Round your answer to four decimal places.)


(b)

 Find a 95% confidence interval for p. (For each answer, enter a number. Round your answers to three decimal places.)
lower limit     
upper limit     

Give a brief explanation of the meaning of the interval.
95% of all confidence intervals would include the true proportion of shoppers who stock up on bargains.5% of all confidence intervals would include the true proportion of shoppers who stock up on bargains.    95% of the confidence intervals created using this method would include the true proportion of shoppers who stock up on bargains.5% of the confidence intervals created using this method would include the true proportion of shoppers who stock up on bargains.

(c)

 As a news writer, how would you report the survey results on the percentage of supermarket shoppers who stock up on items when they find the item is a real bargain?
Report p̂ along with the margin of error.Report p̂.    Report the margin of error.Report the confidence interval.

What is the margin of error based on a 95% confidence interval? (Enter a number. Round your answer to three decimal places.)
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