For this code just explain the void pop function, with enough explanation that how it is working
For this code just explain the void pop function, with enough explanation that how it is working. Thanks
#include<iostream>
using namespace std;
int choice, j=0;
int stack[50];
int *top;
bool Exit_Indicator = false;
void displayStack() {
cout << "\n\t~Stack Display~\nTOP ->";
for (int i = j-1; i >= 0; i--)
cout << "\t|\t" << stack[i] << "\t|" << endl;
cout << "\t-----------------";
}
void push(int i)
{
cout << "\n(" << i << ") has been PUSHED into the stack!";
*top = i;
top++;
j++;
}
void pop()
{
if((*(top-2) != 0 && *(top-1)!= 0) || (*(top-2) == 0 && *(top-1)!= 0)) {
cout << "\n(" << *(top-1) << ") has been POPPED from the stack!";
*(top-1)= 0;
top--;
j--;
}
else{
cout<<"\nTHE STACK IS EMPTY";
}
}
int main() {
int value;
top = stack;
do {
cout << "\n\n------------------------------------------------------------------------\nStack Program Selection UI";
cout << "\n\n1.Push a value into the stack \n2.Pop a value from the stack \n3.List all elements in stack \nOther numbers to exit the program. \n\nYour Choice : ";
cin>>choice;
if (choice == 1)
{
do {
cout << "Enter any values except 0: ";
cin>>value;
} while (value == 0);
push(value);
}
else if (choice == 2)
pop();
else if (choice == 3)
displayStack();
else
Exit_Indicator = true;
} while (Exit_Indicator == false);
return 0;
}
Step by step
Solved in 2 steps