For the two wires and the battery in the circuit: n = 8 x1028 electrons/m³ u = 6 x10-5 (m/s)/(V/m) L₁ = 0.3 m L₂ = 0.18 m A₁ = 8 x10-8 m² A₂ = 1.2 x10-8 m² &= 10 V a) What are the electric fields E₁ and E₂ in the wires? A₁ L₁ + E A₂ L₂

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Chapter1: Units, Trigonometry. And Vectors
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. For the two wires and the battery in the circuit:
n = 8 x1028 electrons/m³
u = 6 x10¹5 (m/s)/(V/m)
L₁ = 0.3 m
L₂ = 0.18 m
A₁ = 8 x10-8 m²
A₂ = 1.2 x108 m²
ε = 10 V
a) What are the electric fields E₁ and E₂ in the wires?
A1
L₁
+
E
A₂
L₂
Transcribed Image Text:. For the two wires and the battery in the circuit: n = 8 x1028 electrons/m³ u = 6 x10¹5 (m/s)/(V/m) L₁ = 0.3 m L₂ = 0.18 m A₁ = 8 x10-8 m² A₂ = 1.2 x108 m² ε = 10 V a) What are the electric fields E₁ and E₂ in the wires? A1 L₁ + E A₂ L₂
b) What is the electric current in wires?
c) What are the wire resistances R₁ and R₂?
Transcribed Image Text:b) What is the electric current in wires? c) What are the wire resistances R₁ and R₂?
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