For the truss shown below, use the method of joints to determine the forces in members EF and BD, and indicate whether they are in tension or compression. [Ans.: FEF = 1 kN (tension); FBD = -4 kN (comp)] %3D 1 kN 2 m 2 m 2 m 2 m 2 m 5 kN Note: The length of each horizontal/vertical member is 2 m and hence 0 = tan-1(2 m/2 m) = 45° %3D

For the truss shown below, use the method of joints to determine the forces in members EF and BD, and indicate whether they are in tension or compression. [Ans.: FEF = 1 kN (tension); FBD = -4 kN (comp)] %3D 1 kN 2 m 2 m 2 m 2 m 2 m 5 kN Note: The length of each horizontal/vertical member is 2 m and hence 0 = tan-1(2 m/2 m) = 45° %3D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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