For the transfer function shown,when omega = infinity, why do we use limits law (where the coefficient is taken in the calculation) to compute it instead of just subbing omega = infinity into the function like how omega = 0 is subbed into the function.I do not understand why when omega = infinity, we take the coefficent of the imaginary numbers to compute the gain. desefvation f formulafor RefrenceRaRIT= VそーViR2VoutT- VsRitRet RgViRi+R2+juseVsValtage= RIVout - Lx R2 [ elements are in leus10lame umrendwll floo ]Ri+RstR3VoutR2R2Ns%3DRi+RattweRitRetR3R3VsRitRztR3Tranyor funelionR jwejux (Ri+R2) +1VoutReUPnRitRet FweLohenlim Hlje)LimmX = MR2 jusejwecRi+Ro)+1lim1つのatnbitluy uing limit fomula, Conefder only coeffrient g oR2Ri+R282 CRitR2)auount the fmaginayThat meausThe cfruit is given as High pas felter (dytem).at loeo frequentygainhave to conifdered only high "frequency & fom aboueis vesy smale (negligroli). So wecalculation we can eaily bee that gain at high frequeny(w0) is R2. That's why take Tnto acout R,RitReRitR2w

I think if you put w=∞ The transfer function become ∞/∞ . And we know that ∞/∞ is an indeterminstic…

Answered: For the transfer function shown, when…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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For the transfer function shown,

when omega = infinity, why do we use limits law (where the coefficient is taken in the calculation) to compute it instead of just subbing omega = infinity into the function like how omega = 0 is subbed into the function.

I do not understand why when omega = infinity, we take the coefficent of the imaginary numbers to compute the gain.

desefvation f formula
for Refrence
Ra
RI
T= V
そー
Vi
R2
Vout
T- Vs
RitRet Rg
Vi
Ri+R2+
juse
Vs
Valtage
= RI
Vout - Lx R2 [ elements are in leus
10lame umrend
wll floo ]
Ri+RstR3
Vout
R2
R2
Ns
%3D
Ri+Rat
twe
RitRetR3
R3
Vs
RitRztR3
Tranyor funelion
R jwe
jux (Ri+R2) +1
Vout
Re
UPn
RitRet Fwe
Lohen
lim Hlje)
Lim
mX = M
R2 juse
jwecRi+Ro)+1
lim
1つの
atnb
it
luy uing limit fomula, Conefder only coeffrient g o
R2
Ri+R2
82 CRitR2)
auount the fmaginay
That meaus
The cfruit is given as High pas felter (dytem).
at loeo frequenty
gain
have to conifdered only high "frequency & fom aboue
is vesy smale (negligroli). So we
calculation we can eaily bee that gain at high frequeny
(w0) is R2. That's why take Tnto acout R,
RitRe
RitR2
w

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