For the system shown in figure, voltages V2. V3 and angles 82, 8z arecalculated using Newton-Raphson method. shunt line charging admittancesare neglected. All the values are given in per unit on 100MVA base.Calculate the complex power flows S12 and S32 in actual units.Z12 = 0.01+ j0.02Z3 = 0.02 + j0.04PLSlack busV=1.0/0°V = 0.96L-1.67°V, = 0.882-5.48°(estimated time to answer this question: 13 minutes)

The given system diagram is shown below,…

Answered: For the system shown in figure,…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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A three-phase balanced load of 15A per phase is supplied by a steel wire armoured cable with a c.s.a. of 2.5mm². The voltage drop for this cable is 15mv/A/m and the circuit is 40m long. Calculate the voltage drop in the cable.
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Eo(LL) (V) a) 3000 b) 2500 2000 1500 1000 500 0 No-load excitation curve @3600rpm 0 1 2 3 4 5 6 DC Excitation current (A) 7 The figure above shows the no-load excitation (LL) curve of a 3-ph, 2-pole, 60 Hz, 1000 kVA, 2.3 kV synchronous alternator at rated speed. The alternator has negligible resistance and Synchronous Reactance Xs = 1.2 n/phase. If the alternator is synchronized to the Power Grid at 2.3 kV (Line to Line), calculate the following: 8 9 10 The value of excitation current required for full load current at 0.7 pf lagging (over-excited). |EO(LL)I IF The alternator current and reactive power when it is delivering 80% rated power (0.8 MW) and its DC excitation current is 4 A. IL Q3ph
A 3Ø, Y-connected alternator is rated at 1,600KVA, 13.5KVv. The armature effective AC resistance per phase is 1.50. The percentage regulation for a load of 1,280kW at unity power factor is 3.5%. Determine: (a) synchronous reactance of the alternator (b) %VR at full-load 0.8pf leading (c) What is the effect on %VR value if taken at half-load lagging pf? Justify and explain briefly your answer on one(1) sentence.
A synchronous generator is rated 645 MVA, 24 kV, 0.9 pf lagging. It has a synchronous reactance 1.2 . The generator is feeding full load at 0.9 pf lagging at rated voltage. Calculate: (a) Excitation emf (E,) and power angle 8 (b) Reactive power drawn by the load Carry out calculations in pu form and convert the result to actual values.
What are FACTS (Flexible Alternating Current Transmission Systems) devices, and how do they enhance power system control?
A Single Area consists of 3 generating units (G1/G2/G3) with the following characteristics: G1: 250 MVA rating, R1 = 0.02 pu (on the 250 MVA base), initial output P1 = 200 MW. G2: 350 MVA rating, R2 = 0.015 pu (on the 350 MVA base), initial output P2 = 300 MW. 0.03 pu (on the 300 MVA base), initial output P3 = 150 MW. G3: 300 MVA rating, R3 = The frequency of the system is 60 Hz. Assuming D = 1 pu on a common base of 1000 MVA, what is the new generation output for G3 for a load increase of 75 MW? Select one: O a. 190.55 MW O b. None of these O c. 203.38 MW d. 166.01 MW
Q3: A synchronous generator with peak generated voltage Vg which is connected to a lighting arrester through a transmission line with characteristics impedance ZL and the lighting arrester equal to the one half of ZL. Let the generator characteristic impedance be one third of ZL. Determine:(i) Calculate the current in the lighting arrester, (ii) Calculate the voltage in lighting arrester, and (iii) the value of lighting arrester resistance must be connected to transfer maximum power?
The figure below shows the one-line diagram of a four- bus power system. The voltages, the scheduled real power and reactive powers, and the reactances of transmission lines are marked at this one line diagram (The voltages and reactances are in PU referred to 100 MW base. The active power P2 in MW is the last three digits (from right) of your registration number (i.e for the student that has a registration number 202112396, P2 =396). [10] Starting from an estimated voltage at bus 2, bus 3, and bus 4 equals V2 (0) = 1.15<0°, V3 = 1.15 < 0°, V4 1.1< 0°. 1- Specify the type of each bus and known & unknown quantities at each bus. 2- Find the elements of the second row of the admittance matrix (i.e. [Y21 Y22 Y23 Y24]). 3- Using Gauss-Siedal fınd the voltage at bus 2 after the first iteration. 4- Using Newton-Raphson, calculate: |- The value of real power (P2), at bus 2 after the first iteration. Il- The second element in the first row of the Jacobian matrix after the first iteration. 2 P2…
X₂=0.1 1 XL +03 Soto X₁ = 0.2 X = 0.1 X = 0.1 Above is the one-line diagram of a simple power system. Each generator is represented by an emf behind the subtransient reactance. All impedances are expressed in per unit on a common base. All resistances and shunt capacitance are neglected. The generators are operating on no load at their rated voltage with their emfs in phase. A symmetrical fault occurs at bus 1 through a fault impedance Z, =j0.08 per unit. a) Using Thevenin's Theorem, determine the impedance to the point of fault and the fault current in per unit. b) Find the bus voltages and line currents during the fault. 2 O oto
3. A circuit consists of two impedances. Z1 =20230° and Z2 =25260° 2, in parallel, supplied by a source voltage V=1002600 volts. Determine the power triangle for each of the impedances and for the source.

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