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For the system at right, M = 250ft*lb, F, = 40 lb, a = 5.8 ft, b : 5.3 ft, c = 4.1 ft, 0 = 22°. Calculate F, such that an equivalent system with all forces and moments located at point A creates a total moment @ A = 0 ft*lb. For the equivalent system what is the final force @ A in cartesian form? A b

For the system at right, M = 250ft*lb, F, = 40 lb, a = 5.8 ft, b : 5.3 ft, c = 4.1 ft, 0 = 22°. Calculate F, such that an equivalent system with all forces and moments located at point A creates a total moment @ A = 0 ft*lb. For the equivalent system what is the final force @ A in cartesian form? A b

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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**Problem Statement:** For the system on the right, the following parameters are given: - \( M_B = 250 \, \text{ft} \cdot \text{lb} \) - \( F_1 = 40 \, \text{lb} \) - \( a = 5.8 \, \text{ft} \) - \( b = 5.3 \, \text{ft} \) - \( c = 4.1 \, \text{ft} \) - \( \Theta = 22^\circ \) Calculate \( F_2 \) such that an equivalent system with all forces and moments located at point A creates a total moment at \( A = 0 \, \text{ft} \cdot \text{lb} \). For the equivalent system, what is the final force at point A in Cartesian form? **Diagram Explanation:** The diagram represents an L-shaped system supported at point B with an applied moment \( M_B \) causing a counterclockwise rotation. Two forces, \( F_1 \) and \( F_2 \), act on the system. \( F_1 \) is at an angle \( \Theta \) with the horizontal along the member CD, and \( F_2 \) acts vertically upwards at point D. - Point A is located at the extremity along the horizontal direction from B with a distance `a`. - Point B is where the moment \( M_B \) is applied. - Point C and D form the vertical section, with D at a distance `c` from C. - The angle \( \Theta = 22^\circ \) defines the inclination of force \( F_1 \) from the horizontal. The objective is to adjust \( F_2 \) such that the net moment about point A is zero and to determine the effective Cartesian force at point A.
Transcribed Image Text:**Problem Statement:** For the system on the right, the following parameters are given: - \( M_B = 250 \, \text{ft} \cdot \text{lb} \) - \( F_1 = 40 \, \text{lb} \) - \( a = 5.8 \, \text{ft} \) - \( b = 5.3 \, \text{ft} \) - \( c = 4.1 \, \text{ft} \) - \( \Theta = 22^\circ \) Calculate \( F_2 \) such that an equivalent system with all forces and moments located at point A creates a total moment at \( A = 0 \, \text{ft} \cdot \text{lb} \). For the equivalent system, what is the final force at point A in Cartesian form? **Diagram Explanation:** The diagram represents an L-shaped system supported at point B with an applied moment \( M_B \) causing a counterclockwise rotation. Two forces, \( F_1 \) and \( F_2 \), act on the system. \( F_1 \) is at an angle \( \Theta \) with the horizontal along the member CD, and \( F_2 \) acts vertically upwards at point D. - Point A is located at the extremity along the horizontal direction from B with a distance `a`. - Point B is where the moment \( M_B \) is applied. - Point C and D form the vertical section, with D at a distance `c` from C. - The angle \( \Theta = 22^\circ \) defines the inclination of force \( F_1 \) from the horizontal. The objective is to adjust \( F_2 \) such that the net moment about point A is zero and to determine the effective Cartesian force at point A.
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