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For the structures below, please indicate whether the compound is reducing or non-reducing, and please justify your answers. NO₂ NO₂ a. b. с. d. 02N НО НО- Но НО- НО НО- ОН ОН ОН ОН Но ОН ОН НО НО НО NO2 НО NO₂ НО Но ОН ОН ОН ОН ОН -ОН NO₂ NO₂

For the structures below, please indicate whether the compound is reducing or non-reducing, and please justify your answers. NO₂ NO₂ a. b. с. d. 02N НО НО- Но НО- НО НО- ОН ОН ОН ОН Но ОН ОН НО НО НО NO2 НО NO₂ НО Но ОН ОН ОН ОН ОН -ОН NO₂ NO₂

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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**Title: Identifying Reducing and Non-Reducing Compounds** **Instructions:** For the structures below, please indicate whether the compound is reducing or non-reducing, and please justify your answers. **Graphical Representations:** **a. Structure A:** - This is a disaccharide structure with several NO₂ groups attached. - The terminal sugar units are linked through an acetal linkage with no free anomeric carbon, typically characteristic of non-reducing sugars. **b. Structure B:** - This is a disaccharide with hydroxyl (OH) groups noted. - The second sugar in the linkage has a free anomeric carbon (not participating in a glycosidic bond), indicating this structure is likely a reducing sugar. **c. Structure C:** - Similar to structure B, this structure shows a disaccharide. - The presence of a free anomeric carbon suggests a reducing sugar. **d. Structure D:** - Another disaccharide, structured similarly to B and C. - Again, a free anomeric carbon is present, indicating a reducing sugar. **Conclusion:** - **Structure A** is non-reducing due to the absence of a free anomeric carbon. - **Structures B, C, and D** are reducing sugars, as evidenced by the presence of free anomeric carbons, which can engage in redox reactions. **Educational Notes:** Reducing sugars have free aldehyde or ketone groups in solution, allowing them to act as reducing agents. Non-reducing sugars do not have such free groups available. Identifying the presence or absence of a free anomeric carbon is key to determining the reducing nature of the compound.
Transcribed Image Text:**Title: Identifying Reducing and Non-Reducing Compounds** **Instructions:** For the structures below, please indicate whether the compound is reducing or non-reducing, and please justify your answers. **Graphical Representations:** **a. Structure A:** - This is a disaccharide structure with several NO₂ groups attached. - The terminal sugar units are linked through an acetal linkage with no free anomeric carbon, typically characteristic of non-reducing sugars. **b. Structure B:** - This is a disaccharide with hydroxyl (OH) groups noted. - The second sugar in the linkage has a free anomeric carbon (not participating in a glycosidic bond), indicating this structure is likely a reducing sugar. **c. Structure C:** - Similar to structure B, this structure shows a disaccharide. - The presence of a free anomeric carbon suggests a reducing sugar. **d. Structure D:** - Another disaccharide, structured similarly to B and C. - Again, a free anomeric carbon is present, indicating a reducing sugar. **Conclusion:** - **Structure A** is non-reducing due to the absence of a free anomeric carbon. - **Structures B, C, and D** are reducing sugars, as evidenced by the presence of free anomeric carbons, which can engage in redox reactions. **Educational Notes:** Reducing sugars have free aldehyde or ketone groups in solution, allowing them to act as reducing agents. Non-reducing sugars do not have such free groups available. Identifying the presence or absence of a free anomeric carbon is key to determining the reducing nature of the compound.
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