For the RL circuit as shown in the following: R = 150 Ohms, L= 0.38 mH and E = 12.00 V a Awww Leeeee- R 23. find the time constant. a. 2.53 ms b. 2.53 µs c. 2.53 sec d. none of these · 24. When the switch is thrown to point a, what is the current at t 5.0 µs ? a. 28.7 mA b. 34.7 mA c. 68.9 mA d. 11.0 mA

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Chapter1: Units, Trigonometry. And Vectors
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 23 and 24

**For the RL Circuit as Shown Below:**

Given values:
- Resistance (R) = 150 Ohms
- Inductance (L) = 0.38 mH
- Voltage (E) = 12.00 V

The diagram depicts an RL circuit with a switch between two positions (a and b). The resistor (R) and the inductor (L) are in series with the voltage source (E).

**Questions:**

23. *Find the time constant.*

   Options:
   - a. 2.53 ms
   - b. 2.53 μs
   - c. 2.53 sec
   - d. None of these

24. *When the switch is thrown to point a, what is the current at t = 5.0 μs?*

   Options:
   - a. 28.7 mA
   - b. 34.7 mA
   - c. 68.9 mA
   - d. 11.0 mA

This exercise involves calculating the time constant for the RL circuit and determining the current in the circuit after a specific time when the switch is closed.
Transcribed Image Text:**For the RL Circuit as Shown Below:** Given values: - Resistance (R) = 150 Ohms - Inductance (L) = 0.38 mH - Voltage (E) = 12.00 V The diagram depicts an RL circuit with a switch between two positions (a and b). The resistor (R) and the inductor (L) are in series with the voltage source (E). **Questions:** 23. *Find the time constant.* Options: - a. 2.53 ms - b. 2.53 μs - c. 2.53 sec - d. None of these 24. *When the switch is thrown to point a, what is the current at t = 5.0 μs?* Options: - a. 28.7 mA - b. 34.7 mA - c. 68.9 mA - d. 11.0 mA This exercise involves calculating the time constant for the RL circuit and determining the current in the circuit after a specific time when the switch is closed.
Expert Solution
Step 1

23. Time constant

τ=LR=0.38×10-3H150 Ω   =2.53 μs

Therefore, the correct option is b) 2.53 μs

 

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