For the reaction shown, seledt the expected major organic product. H2 Pt II IV V.

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### Understanding Hydrocarbon Reactions with Catalysts

For the reaction shown, select the expected major organic product.

#### Reaction and Conditions:
A hydrocarbon with a triple bond (an alkyne) undergoes hydrogenation in the presence of a platinum (Pt) catalyst.

**Reactants:**
- Hydrogen gas (H₂)
- Platinum (Pt) catalyst
- Triple-bonded hydrocarbon (alkyne)

**Question:**
Which of the following structures is the correct major product of the reaction?

#### Answer Choices:
- **A. Compound I:** Depicts a fully saturated hydrocarbon (no double or triple bonds).
- **B. Compound II:** Illustrates a hydrocarbon with a single double bond (cis configuration).
- **C. Compound III:** Shows a hydrocarbon with a single double bond (trans configuration).
- **D. Compound IV:** Displays a hydrocarbon with no double or triple bonds.
- **E. Compound V:** Represents the original compound with a triple bond retained.

#### Answer Options Detail:
- If the alkyne were to be fully hydrogenated in excess H₂, it would become an alkane. This would be represented by options A (I) or D (IV). Both I and IV show fully saturated hydrocarbons.
- If the alkyne were to be selectively hydrogenated to an alkene, the product would retain a double bond. This could result in either a cis (Z) or trans (E) configuration, represented by options B (II) or C (III).
- If no reaction were to occur, the structure would remain as shown in option E (V).

#### Conclusion:
During hydrogenation in the presence of a platinum catalyst, the triple bond in the alkyne is typically fully reduced to a single bond, resulting in a completely saturated hydrocarbon.

The expected major organic product, therefore, aligns with option **A (I)**.
Transcribed Image Text:### Understanding Hydrocarbon Reactions with Catalysts For the reaction shown, select the expected major organic product. #### Reaction and Conditions: A hydrocarbon with a triple bond (an alkyne) undergoes hydrogenation in the presence of a platinum (Pt) catalyst. **Reactants:** - Hydrogen gas (H₂) - Platinum (Pt) catalyst - Triple-bonded hydrocarbon (alkyne) **Question:** Which of the following structures is the correct major product of the reaction? #### Answer Choices: - **A. Compound I:** Depicts a fully saturated hydrocarbon (no double or triple bonds). - **B. Compound II:** Illustrates a hydrocarbon with a single double bond (cis configuration). - **C. Compound III:** Shows a hydrocarbon with a single double bond (trans configuration). - **D. Compound IV:** Displays a hydrocarbon with no double or triple bonds. - **E. Compound V:** Represents the original compound with a triple bond retained. #### Answer Options Detail: - If the alkyne were to be fully hydrogenated in excess H₂, it would become an alkane. This would be represented by options A (I) or D (IV). Both I and IV show fully saturated hydrocarbons. - If the alkyne were to be selectively hydrogenated to an alkene, the product would retain a double bond. This could result in either a cis (Z) or trans (E) configuration, represented by options B (II) or C (III). - If no reaction were to occur, the structure would remain as shown in option E (V). #### Conclusion: During hydrogenation in the presence of a platinum catalyst, the triple bond in the alkyne is typically fully reduced to a single bond, resulting in a completely saturated hydrocarbon. The expected major organic product, therefore, aligns with option **A (I)**.
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