For the reaction shown, add curved arrows for each step, then complete the statements. H. H3C, c=c° H. CH3 HBr H3C C-C CH3 -CCH3 H. Br H. :Br:
For the reaction shown, add curved arrows for each step, then complete the statements. H. H3C, c=c° H. CH3 HBr H3C C-C CH3 -CCH3 H. Br H. :Br:
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I need help with the arrows I’m so confused
![### Reaction Mechanism with Curved Arrows
**Objective:**
For the reaction shown, add curved arrows for each step, then complete the statements regarding the hybridization of the carbons.
---
**Step 1: Formation of the Carbocation Intermediate**
- **Reactants:**
- An alkene with the structure H₃C-C=CH-CH₃ reacts with HBr.
- **Illustration:**
- The alkene is shown with double-bonded carbons.
- Curved arrows are needed to show the movement of electrons from the double bond to form a bond with H from HBr.
- **Intermediate:**
- The result is a carbocation intermediate, where the positive charge is located on one of the carbons of the former double bond.
**Diagram:**
- The double bond of the alkene attacks the H of HBr, forming a hydrogen-carbon bond.
- The bond between H and Br breaks, leaving a bromide ion (Br⁻).
---
**Step 2: Formation of the Product**
- **Process:**
- The bromide ion (Br⁻) will attack the carbocation to form the final product.
- **Completion:**
- This results in the addition of Br to the carbon atom that bears the positive charge, yielding the final product.
**Diagram:**
- Br⁻ attacks the carbocation, and a new C-Br bond is formed.
---
**Hybridization Statements:**
1. **The hybridization of the alkene carbons is** \[ \text{sp}^2 \].
2. **The hybridization of the carbocation is** \[ \text{sp}^2 \].
3. **The hybridization of the carbons in the product is** \[ \text{sp}^3 \].
---
This detailed explanation and diagrammatic representation help you understand the electron movement and structural changes in the alkene addition reaction with HBr.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8a28a380-2121-4133-b35d-e9a8f94c0516%2F6e963b47-d6b2-4f41-abdf-ee9335aa22e2%2Fg102fuf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Reaction Mechanism with Curved Arrows
**Objective:**
For the reaction shown, add curved arrows for each step, then complete the statements regarding the hybridization of the carbons.
---
**Step 1: Formation of the Carbocation Intermediate**
- **Reactants:**
- An alkene with the structure H₃C-C=CH-CH₃ reacts with HBr.
- **Illustration:**
- The alkene is shown with double-bonded carbons.
- Curved arrows are needed to show the movement of electrons from the double bond to form a bond with H from HBr.
- **Intermediate:**
- The result is a carbocation intermediate, where the positive charge is located on one of the carbons of the former double bond.
**Diagram:**
- The double bond of the alkene attacks the H of HBr, forming a hydrogen-carbon bond.
- The bond between H and Br breaks, leaving a bromide ion (Br⁻).
---
**Step 2: Formation of the Product**
- **Process:**
- The bromide ion (Br⁻) will attack the carbocation to form the final product.
- **Completion:**
- This results in the addition of Br to the carbon atom that bears the positive charge, yielding the final product.
**Diagram:**
- Br⁻ attacks the carbocation, and a new C-Br bond is formed.
---
**Hybridization Statements:**
1. **The hybridization of the alkene carbons is** \[ \text{sp}^2 \].
2. **The hybridization of the carbocation is** \[ \text{sp}^2 \].
3. **The hybridization of the carbons in the product is** \[ \text{sp}^3 \].
---
This detailed explanation and diagrammatic representation help you understand the electron movement and structural changes in the alkene addition reaction with HBr.
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