For the reaction shown, add curved arrows for each step, then complete the statements. H. H3C, c=c° H. CH3 HBr H3C C-C CH3 -CCH3 H. Br H. :Br:

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I need help with the arrows I’m so confused
### Reaction Mechanism with Curved Arrows

**Objective:**
For the reaction shown, add curved arrows for each step, then complete the statements regarding the hybridization of the carbons.

---

**Step 1: Formation of the Carbocation Intermediate**

- **Reactants:** 
  - An alkene with the structure H₃C-C=CH-CH₃ reacts with HBr.
 
- **Illustration:**
  - The alkene is shown with double-bonded carbons.
  - Curved arrows are needed to show the movement of electrons from the double bond to form a bond with H from HBr.

- **Intermediate:**
  - The result is a carbocation intermediate, where the positive charge is located on one of the carbons of the former double bond.

**Diagram:**
- The double bond of the alkene attacks the H of HBr, forming a hydrogen-carbon bond.
- The bond between H and Br breaks, leaving a bromide ion (Br⁻).

---

**Step 2: Formation of the Product**

- **Process:**
  - The bromide ion (Br⁻) will attack the carbocation to form the final product.

- **Completion:**
  - This results in the addition of Br to the carbon atom that bears the positive charge, yielding the final product.

**Diagram:**
- Br⁻ attacks the carbocation, and a new C-Br bond is formed.

---

**Hybridization Statements:**

1. **The hybridization of the alkene carbons is** \[ \text{sp}^2 \].

2. **The hybridization of the carbocation is** \[ \text{sp}^2 \].

3. **The hybridization of the carbons in the product is** \[ \text{sp}^3 \].

---

This detailed explanation and diagrammatic representation help you understand the electron movement and structural changes in the alkene addition reaction with HBr.
Transcribed Image Text:### Reaction Mechanism with Curved Arrows **Objective:** For the reaction shown, add curved arrows for each step, then complete the statements regarding the hybridization of the carbons. --- **Step 1: Formation of the Carbocation Intermediate** - **Reactants:** - An alkene with the structure H₃C-C=CH-CH₃ reacts with HBr. - **Illustration:** - The alkene is shown with double-bonded carbons. - Curved arrows are needed to show the movement of electrons from the double bond to form a bond with H from HBr. - **Intermediate:** - The result is a carbocation intermediate, where the positive charge is located on one of the carbons of the former double bond. **Diagram:** - The double bond of the alkene attacks the H of HBr, forming a hydrogen-carbon bond. - The bond between H and Br breaks, leaving a bromide ion (Br⁻). --- **Step 2: Formation of the Product** - **Process:** - The bromide ion (Br⁻) will attack the carbocation to form the final product. - **Completion:** - This results in the addition of Br to the carbon atom that bears the positive charge, yielding the final product. **Diagram:** - Br⁻ attacks the carbocation, and a new C-Br bond is formed. --- **Hybridization Statements:** 1. **The hybridization of the alkene carbons is** \[ \text{sp}^2 \]. 2. **The hybridization of the carbocation is** \[ \text{sp}^2 \]. 3. **The hybridization of the carbons in the product is** \[ \text{sp}^3 \]. --- This detailed explanation and diagrammatic representation help you understand the electron movement and structural changes in the alkene addition reaction with HBr.
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