For the reaction SbCl5(g) S SÜCI3(g) + Cl2{g). AG'F (SbCls) = -334.34 kJ/mol AG'f (SbCl3) = -301.25 kJ/mol AH'F (SbCls) = -394.34 kJ/mol AH'f (SbCl3) = -313.80 kJ/mol Calculate the value of the equilibrium constant (Kp) for this reaction at 298 K.

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Chapter1: Chemical Foundations
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1.38 x 10-6
1.78 x 10 6
1.58 x 10 6
None of the above
1.98 x 10-6
Transcribed Image Text:Saved Help 1.38 x 10-6 1.78 x 10 6 1.58 x 10 6 None of the above 1.98 x 10-6
For the reaction SbCi5(g) 5 SÜC13(g) + Cl2(g).
AG'F (SbCls) = -334.34 kJ/mol
AG'f (SbCl3) = -301.25 kJ/mol
AH'F (SbCi5) = -394.34 kJ/mol
AH°r (SbCl3) = -313.80 kJ/mol
Calculate the value of the equilibrium constant (Kp) for this reaction at 298 K.
Multiple Choice
1.38 x 10-6
Transcribed Image Text:For the reaction SbCi5(g) 5 SÜC13(g) + Cl2(g). AG'F (SbCls) = -334.34 kJ/mol AG'f (SbCl3) = -301.25 kJ/mol AH'F (SbCi5) = -394.34 kJ/mol AH°r (SbCl3) = -313.80 kJ/mol Calculate the value of the equilibrium constant (Kp) for this reaction at 298 K. Multiple Choice 1.38 x 10-6
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