For the reaction PCl3​(g)+Cl2​(g)<---> PCl5​(g) the initial mixture contains 3.25 mol PCl3, 6.30 mol Cl2, and no moles of PCl5. At equilibrium, 1.75 mol of PCl3 remains.   How many moles of Cl2 and PCl5 are present at equilibrium? (Be sure to give your answer to two decimal places.)     ? mol Cl2         ? mol PCl5

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