I need help with this question please For the reaction, PCI5 (g) = PCI3 (g)+ Cl₂ (g)a) Calculate the K for the equilibrium reaction at 25 °C given that the AGOrxn is 35.4kJ/mol.b) Calculate the AG for the reaction if the partial pressures are PPC15 =0.0029 atm; PPC13=0.27 atm; PC152=0.40 atm.

Given thatT = 25 °C = 25 +273.15 = 298.15 KR = gas constant = 8.314 J/(mol.K)

For the reaction, PCI5 (g) PCl3 (g)+ Cl₂ (g) a) Calculate the K for the equilibrium reaction at 25 °C given that the AGºrxn is 35.4 kJ/mol. b) Calculate the AG for the reaction if the partial pressures are PPCI5 =0.0029 atm; PPC13 =0.27 atm; PC152=0.40 atm.

For the reaction, PCI5 (g) PCl3 (g)+ Cl₂ (g) a) Calculate the K for the equilibrium reaction at 25 °C given that the AGºrxn is 35.4 kJ/mol. b) Calculate the AG for the reaction if the partial pressures are PPCI5 =0.0029 atm; PPC13 =0.27 atm; PC152=0.40 atm.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

I need help with this question please

For the reaction, PCI5 (g) = PCI3 (g)+ Cl₂ (g)
a) Calculate the K for the equilibrium reaction at 25 °C given that the AGOrxn is 35.4
kJ/mol.
b) Calculate the AG for the reaction if the partial pressures are PPC15 =0.0029 atm; PPC13
=0.27 atm; PC152=0.40 atm.

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